<h3>
Answer: Not direct variation</h3>
The reason why is because it can't be written in the form y = kx
If we solved the given equation for y, we get y = -x+6. It has a y intercept of 6, but it should be zero if we wanted a direct variation equation.
Answer:
Area=36
Step-by-step explanation:
Area of rhombus: diagonal 1 x diagonal 2 divided by 2.
To find the area of a rhombus, you need to find the length of both diagonals(which is the distance between 2 points across from each other).
First, find the distance between -8 and 4 which is 12.
Next, find the distance between -1 and -7 which is 6.
12 x 6 =72
72/2=36
For parts A, B, C, and D you most likely created a line. What question E is asking is for you to create a line that is perpendicular to the line you already created that also passes through the point (1,1). What is important to understand here is that the slope of the perpendicular line is the negative reciprocal of the original line's slope... if the original slope is (-4/3) than the perpendicular slope is (3/4)... then you should just plug that new slope into point-slope form or slope-intercept form to get your equation... y-y1 = m(x-x1) ... y-1= (3/4)(x-1) ... so it would be y=(3/4)x + 1/4 then for part f just convert into standard form which is just manipulating the variables... look up standard form equation on Google and manipulate the variables from there.
Answer:
y=0.5x + 5
Step-by-step explanation:
The points are (0,5) and (-10,0)
to find the slope do
0-5/-10-0 = 5/10 = 1/2 = 0.5
next plug one of the points into point slope formula
y-y1=m(x-x1)
lets use the point (-10,0)
y1=0
x1= -10
m= 0.5
y-0=0.5(x- -10)
y = 0.5(x+10)
distribute the 0.5
y=0.5x+5
Answer:
can you plz send the full image
