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Ksivusya [100]
3 years ago
5

How can Ari simplify the following expression? StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1

Over a minus 3 EndFraction
Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0

Answer:

-\frac{8}{3}

Step-by-step explanation:

Given

\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}

Required

Simpify

The very first step is to take LCM of the given expression

\frac{-10 -4 - 2}{6}

Perform arithmetic operations o the numerator

-\frac{16}{6}

Divide the numerator and denominator by 2

-\frac{16/2}{6/2}

-\frac{8}{3}

The expression can't be further simplified;

Hence, \frac{5}{-3} - \frac{4}{2} + \frac{1}{-3} = -\frac{8}{3}

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According to a study conducted in one city, 35% of adults in the city have credit card debts more than $2.000. A simple random s
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Answer:

Binomial; \mu p=87.5, \sigma p=7.542

Step-by-step explanation:

  • a distribution is said be a binomial distribution iff
  1. The probability of success of that event( let it be p) is same for every trial
  2. each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
  3. there are fixed number of trials (n)
  4. the trials are independent
  • here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)
  • here n=250
  • the probability of success(0.35) is same for every trial

(35/100=0.35 is the required p here)

  • \mu_{p} =n*p=250*\frac{35}{100} =250*0.35=87.5

[since, the formula for \mu _{p} =n*p ]

  • \sigma _{p} =\sqrt{n*(p)*(1-p)} = \sqrt{250*0.35*(1-0.35)} = 7.542 ( approximately)

[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}

  • therefore, it is Binomial; \mu p=87.5, \sigma p=7.542

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The answer would be 0.54
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Step-by-step explanation:

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