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ryzh [129]
3 years ago
9

his garden is rectangular and the garden measure 33 feet by 39 feet. And the garden has a path around it has 3 feet wide. How mu

ch material does it need to enclose the garden and path?
Mathematics
1 answer:
leva [86]3 years ago
8 0

Answer:

I think 432 ft

Step-by-step explanation:

p=2w+2l

(2*33)+(2*39)=144

432ft

sorry if this is not the right answer

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Why do a cars tires need more air in the winter than they do in the summer
kodGreya [7K]
I believe the pressure inside the tires decreases in the winter because of the cold and increases in the summer when the air is heated up making it expand and add more pressure
4 0
3 years ago
Read 2 more answers
If the perimeter of a rectangle or piece of glass is 26 inches and the length is 4 inches longer than twice the width and what a
cricket20 [7]
2(2w+4+w)=26; 6w+8=26; w=3, l=10

5 0
3 years ago
what is the slope of the line through (1,0)(1,0)left parenthesis, 1, comma, 0, right parenthesis and (3,8)(3,8)
77julia77 [94]

The slope of the line passing through (1 , 0) and (3 , 8) is 4.

Slope, commonly represented by the letter m, is a value that describes the steepness and direction of a line. The slope of a line is also called its gradient or rate of change.

It is the vertical change in y divided by the horizontal change in x, sometimes called rise over run. The slope formula uses two points, (x_{1}, y_{1} ) and (x_{2}, y_{2} ), to calculate the change in y over the change in x.

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1} }     where

x_{1} = 1

y_{1} = 0

x_{2} = 3

y_{2} = 8

Substituting the values,

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1} } =\frac{8-0}{3-1} =\frac{8}{2}=4

Hence, he slope of the line passing through (1 , 0) and (3 , 8) is 4.

For more example on slope of line, visit brainly.com/question/3493733.

#SPJ4

7 0
2 years ago
Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a red mar
swat32

Assuming that each marble can be picked with equal probability, we notice that there is a total of

4+2+5+1+7 = 19

marbles, of which 2 are red.

So, the probability of picking a red marble is

\dfrac{2}{19}

In fact, as in any other case of (finite) equidistribution, we used the formula

P(\text{event}) = \dfrac{\text{number of favourable cases}}{\text{number of all possible cases}}

4 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
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