Answer:
1/9
Step-by-step explanation:
For these questions, you have to first find the probability of each event individually occuring then multiply these two probabilities together. So, lets first find the probability of Event 1 occuring (rolling a number higher than 1). On a dice, we know that there are 6 numbers (1, 2, 3, 4, 5, 6) of which the numbers 5 and 6 are higher than 4. Therefore, the proability of Event 1 occuring is 2/6 = 1/3. Now, we find the probability of event 2 occuring.
We know that there are 3 options on the spinner that the arrow can land on. It is also evident that they all have the same chance of landing on it. Therefore, the possibility is 1/3.
Now that we have both of our probabilities, we multiply the answer together.
Therefore, our answer will be:
1/3 x 1/3, which gives 1/9.
Answer:
Step-by-step explanation:
f(x) = x^2 + 4x + 4
f(x + a) = (x + a)^2 + 4(x + a) + 4
f(x + a) = x^2 + 2ax + a^2 + 4x + 4a + 4 Now combine like terms and use the distributive property.
f(x + a) = x^2 + (2a + 4)x + a^2 + 4a + 4
We are told that f(x + a) = x^2 - 6x + 9
So that means that
2a + 4 = - 6 Subtract 4 from both sides.
2a = - 6 - 4
2a = - 10 Divide by 2
a = - 10/2
a = - 5.
But you are not finished. You have to check the last part.
a^2 + 4x + 4 = 9
(a + 2)^2 = 9
Take the square root of both sides
sqrt(a+ 2)^2 = +/- 3
a+2 = 3
a = 1.
Does this work or is it extraneous? It is extraneous because it will not work for 2(a) + 4 = - 6
You get 6 = - 6 which is not correct. But you did give the second best answer.
a + 2 = - 3
a = - 3 - 2
a = - 5 which agrees with your previous answer.
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This is an extremely hard or tricky or sneaky problem. It takes a lot of conniving to get the right answer and 1 is not a left field answer. It just does not happen to be correct.
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<h3>hope it helps you if it does please mark me as brainliest :-)</h3>
