Ask question

Ask question

All categories

2 years ago

6

The patriot diner sells 2 cheeseburgers and one soda for $11.00 and 3 hamburgersand 2 sodas for $18.00. What is the cost of a ch

eeseburger?

1 answer:

kvasek [131]2 years ago

6 0

Answer: the cost of a cheeseburger is $4

Step-by-step explanation:

Let x represent the cost of one cheeseburgers.

Let y represent the cost of one Soda.

The patriot diner sells 2 cheeseburgers and one soda for $11.00. It means that

2x + y = 11 - - - - - - - - - - - 1

She also sells 3 cheeseburgers and 2 sodas for $18.00. It means that

3x + 2y = 18 - - - - - - - - - - -2

Multiplying equation 1 by 3 and equation 2 by 2, it becomes

6x + 3y = 33

6x + 4y = 36

Subtracting, it becomes.

- y = - 3

y = 3

Substituting y = 3 into equation 1, it becomes

2x + 3 = 11

2x = 11 - 3 = 8

x = 8/2 = 4

You might be interested in

Image<br><br> if there are no fake answers i will do 15 points next time

tekilochka [14]

Answer:

#1) 15*6*7=630CM^3

#2) (50)^3=50*50*50=125,000

Step-by-step explanation:

Trust me my answers are REAL <333

7 0

2 years ago

Select the correct answer. What is the 13th term of this arithmetic sequence? 132, 135, 138, 141, … A. 168 B. 172 C. 176 D. 179

puteri [66]

Answer:

168

Step-by-step explanation:

132, 135, 138, 141, 144, 147, 150, 153, 156, 159, 162, 165, 168

5 0

2 years ago

Consider the following information related to a set of quantitative sample data:

svlad2 [7]

Answer:

(a) There are outliers

(b) $x$ and $x >62$

Step-by-step explanation:

Given

$\sigma = 14.92$

$\bar x = 22.0$

$q_0 = -24$

$q_1 = 14.5$

$q_2 = 24.5$

$q_3 = 33.5$

$q_4 = 64$

Solving (a): Check for outliers

This is calculated using:

$Lower = Q_1 - (1.5 * IQR)$ --- lower bound of outlier

$Upper = Q_3 +(1.5 * IQR)$ --- upper bound of outlier

Where

$IQR = Q_3 - Q_1$

So, we have:

$IQR = 33.5 - 14.5$

$IQR = 19$

The lower bound of outlier becomes

$Lower = Q_1 - (1.5 * IQR)$

$Lower = 14.5 - (1.5 * 19)$

$Lower = 14.5 - 28.5$

$Lower = -14$

The upper bound of outlier becomes

$Upper = Q_3 +(1.5 * IQR)$

$Upper = 33.5 + 1.5 * 19$

$Upper = 33.5 + 28.5$

$Upper = 62$

So, we have:

$-14 \le x \le 62$ --- the range without outlier

Given that:

$q_0 = -24$ --- This represents the lowest data

$q_4 = 64$ --- This represents the highest data

-24 and 64 are out of range of $-14 \le x \le 62$ .

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

$x$ and $x >62$

4 0

2 years ago

What are the steps to solving this problem K + 8\5 = 1k

DaniilM [7]

-- Subtract K from each side of the equation.

8/5 = 0

-- There is no value for K that can make this a true statement. So the original equation has no solution.

8 0

2 years ago

The amount (in megawatts) of energy generated in a country from wind power can be modeled by the function W(t)equalsw0(1.90)

Ad libitum [116K]

Answer with Step-by-step explanation:

We are given that

$W(t)=W_0(1.90)^t$

Where t corresponds to the year 2000=0

a. $W(0)=2540MW$

Substitute the values

$2540\times 10^6=W_0(1.90)^0=W_0$

$W_0=2540MW$

b.In 2004

t=4

$W(4)=2540(1.90)^4$

$W(4)=33101.534 MW$

c.In 2013

t=13

$W(13)=2540(1.9)^{13}=10.68\times 10^6MW$

6 0

2 years ago