Since they are multiples if 12
The possibilities are
12, 12, 156
12,24,144
12,36,132
12,48,120
12,60,108
12,72,96
12,84,84
24,24,132
24,36,120
24,48,108
24,60,96
24,72,84
36,36,108
36,48,96
36,60,84
36,72,72
48,48,84
48,60,72
60,60,60
Hence the probability is 1/19 or 0.0526
According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.
![\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2050-2x%3D110-42x%20%5C%5C%2042x-2x%3D110-50%20%5C%5C%2040x%3D60%20%5C%5C%20x%3D%5Cfrac%7B60%7D%7B40%7D%20%5C%5C%20x%3D%5Cfrac%7B3%7D%7B2%7D%20%5Cend%7Bgathered%7D)
x is 3/2. Replace this value in both expression to find the measure of each angle.
![\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cmeasuredangle1%3D50-2x%20%5C%5C%20%5Cmeasuredangle1%3D50-2%28%5Cfrac%7B3%7D%7B2%7D%29%20%5C%5C%20%5Cmeasuredangle1%3D50-3%20%5C%5C%20%5Cmeasuredangle1%3D47%20%5C%5C%20%5Cmeasuredangle2%3D110-42x%20%5C%5C%20%5Cmeasuredangle2%3D110-42%28%5Cfrac%7B3%7D%7B2%7D%29%20%5C%5C%20%5Cmeasuredangle2%3D110-63%20%5C%5C%20%5Cmeasuredangle2%3D47%20%5Cend%7Bgathered%7D)
The measure of these angles is 47°
14
Divide 98 by 7, you get 14.
This is how many starburst are in each packet.
Answer: x = 9
Step-by-step explanation:
(replace the variables) 6(9)-2(5)^2
(simplified) 54-10^2.... 54-100=-46