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2 years ago

How do you find the phase shift of the trig function y=4sin(pieX+2)-5

1 answer:

max2010maxim [7]2 years ago

5 0

The phase shift is the value of the angle when the variable
in the angle is zero.

The angle in the sin function in this equation is (pi X + 2).

When the variable 'X' is zero, the angle is 2 .

So the phase shift of this sin function is 2 (of whatever
the unit of the angle is ... 2 degrees, 2 radians, etc.)

You might be interested in

What angle is co-terminal with 125 Degrees

Svetradugi [14.3K]

Answer: 125° and -235° Coterminal Angles.

Step-by-step explanation:

Thats it.

6 0

2 years ago

Find the surface area of the part of the circular paraboloid z=x^2+y^2 that lies inside the cylinder X^2+y^2=1

hichkok12 [17]

Answer:

$\mathbf{\dfrac{\pi}{6}[5 \sqrt{5}-1]}$

Step-by-step explanation:

Given that:

The surface area (S.A) $z = x^2 +y^2$

Hence the S.A is of form z = f(x,y)

Then the S.A can be represented with the equation

$A(S) = \iint _D \sqrt{1+ (\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2} \ dA$

where :

D = cylinder $x^2 +y^2 =1$

In polar co-ordinates:

D = {(r, θ): 0≤ r ≤ 1, 0 ≤ θ ≤ 2π)

Similarly, $\dfrac{\partial z}{\partial x} = 2x$ and $\dfrac{\partial z}{\partial y} = 2y$

Therefore;

$S.A = \iint_D \sqrt{1+4x^2+4y^2} \ dA$

$= \iint_D \sqrt{1+4(x^2+y^2)} \ dA$

$= \int^{2 \pi}_{0} \int^{1}_{0} \sqrt{1+4r^2} \ r \ dr \d \theta$

$= [\theta]^{2 \pi}_{0} \dfrac{1}{8}\times \dfrac{2}{3}\begin {bmatrix} (1+4r^2)^{\dfrac{3}{2}}\end {bmatrix}^1_0$

$= 2 \pi \times \dfrac{1}{12}[5^{\dfrac{3}{2}} - 1]$

$\mathbf{=\dfrac{\pi}{6}[5 \sqrt{5}-1]}$

6 0

3 years ago

Help me answer the question pleaseee!!!

vfiekz [6]

Option A,B,C,D,F are False

Option E is True

Step-by-step explanation:

Finding graphs of the equation: y= -4x+6

Checking all the options.

A) (-4,-10)

Plugging value of x as -4 and y as -10

-10=(-4)(-4)+6

-10 = 16+6

-10 ≠ 22

So, both sides of the equation will not be equal.

B) (-4,-22)

Plugging value of x as -4 and y as -22

-22=(-4)(-4)+6

-22=16+6

-22 ≠ 22

So, both sides of the equation will not be equal.

C) (1,10)

Plugging value of x as 1 and y as 10

10=(-4)(1)+6

10 = -4+6

10 ≠ 2

So, both sides of the equation will not be equal.

D) (1,-2)

Plugging value of x as 1 and y as -2

-2=(-4)(1)+6

-2 = -4+6

-2 ≠ 2

So, both sides of the equation will not be equal.

E) (4,-10)

Plugging value of x as 4 and y as -10

-10=(-4)(4)+6

-10 = -16+6

-10 = -10

So, both sides of the equation will be equal.

F) (4,-22)

Plugging value of x as 4 and y as -22

-22=(-4)(4)+6

-22 = -16+6

-22 ≠ -10

So, both sides of the equation will not be equal.

So, Option A,B,C,D,F are False

Option E is True

Keywords: Graph of equations

Learn more about Graph of equations at:

#learnwithBrainly

3 0

3 years ago

What is the value of x which proves that the runways are parallel? What is the measure of the larger angle? (evidently the answe

romanna [79]

I feel like the answer is C

3 0

3 years ago

At a coffee shop, Polly can choose to earn $12 per hour plus a starting bonus of $100 or she can choose to earn $16 per hour wit

vova2212 [387]

Answer:

For the first option 1h for the second option is 7h and she will earn the same which is 112$

Step-by-step explanation:

12 x 1 = 12 + 100 = 112

16 x 17 =112

5 0

2 years ago