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3 years ago

4. A guardrail that runs along the

Mathematics

1 answer:

Vinvika [58]3 years ago

5 0

There are 50 sections.

Step-by-step explanation:

Given,

Length of section = 10 meters

Total length of guardrail = 0.5 km

We will convert this length in meters.

1 km = 1000 meters

0.5 km = 0.5*1000 = 500 meters

Now,

No. of sections = $\frac{Total\ length\ of\ guardrail}{Length\ of\ one\ section}$

No. of sections = $\frac{500}{10}$

No. of sections = 50

There are 50 sections.

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Dennis has 9.5 weeks to prepare for a bike tour If he rides 8.2 miles each week how many miles will he ride before the bike tour

emmasim [6.3K]

If you have to show your work...

8.2 x 9.5

8.2
x 9.5
-----------
410
+ 7380
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7,790 miles

hoped this helped.

6 0

3 years ago

3(q−7)=27 need help plzz 1st peep gets brainlest

ANTONII [103]

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▹ Answer

q = 16

▹ Step-by-Step Explanation

3(q - 7) = 27

3q - 21 = 27

Add 21 to both sides:

21 + 21 = na

27 + 21 = 48

3q = 48

Divide both sides by 3:

3/3 = q

48/3 = 16

q = 16

Hope this helps!

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8 0

3 years ago

Read 2 more answers

What are the factors of 36

nasty-shy [4]

1,36. 2,18. 3,12. 4,9. 6,6. I thibk thats all

4 0

3 years ago

Select the correct answer from each drop-down menu.

german

5 is a coefficient. A coefficient is a number multiplied by a variable.

(2y+13) is a factor. It can be multiplied by 8 to get an extended answer.

-1 is a constant. A constant is a number that does not change.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

x = 2
y = -1

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

4 0

2 years ago