The relative frequency of the marked elks are:
- Male Elk = 7/30
- Female Elk = 4/15
- Adult Elk= 173/450
- Baby Elk = 26/22
<h3>How to determine the relative frequency?</h3>
From the complete question, we have:
- Male = 105
- Female = 120
- Adult = 173
- Baby = 52
- Total = 450
The relative frequency of each is then calculated as:
Male Elk = 105/450
Male Elk = 7/30
Female Elk = 120/450
Female Elk = 4/15
Adult Elk= 173/450
Baby Elk = 52/450
Baby Elk = 26/22
<h3>The number of Elks in the park</h3>
Using the data in (a), we can conclude that:
There are 105 male, 120 female, 173 adult, and 26 baby in the park
Read more about frequency table at:
brainly.com/question/1094036
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Hello,
9)
∠DBC=90-54=36°
∠CAD=∠DBC=36°
10)
∠BOC=1/2(360-2*100)=1/2*160=80°
∠l=1/2∠AOD=1/2∠BOC=40°
11)
JL=10
JA=7==>AL=10-7=3
LC=AL=3
LK=11
CK=11-3=8
KB=KC=8
BJ=JA=7
perimeter=10+11+15=36
The two numbers are very near 7200 and 300. The sum of those is a good estimate of your sum:
... 7200 + 300 = 7500
_____
If you're taught methods of addition that include "make a ten" or "make a hundred", you know you can "borrow" a 1 from 7203 (making it 7202) and loan that 1 to 299 to make it 300. Now, you know your sum is exactly 7202+300 = 7502, with no estimation necessary.
<u>Answer </u><u>:</u>
This figure consists of two shapes that are a rectangle and a square . We will first find the area of rectangle then the square then add them . Let's work on this together ,
- Breadth of rectangle = 4 cm
- Length of rectangle = 4 + 5 + 3
- Length = 12 cm
- Area of rectangle = 12 × 4
- 48 cm²
Area of square ,
Total area of the figure ,
43 students are on each bus
