C.48
110 students
- 42 photography
———
68
Now you must account for the fifteen who are in dual enrollment so 35-15=20
68
- 20
____
48
Answer:
Step-by-step explanation:
a. scalene : Reason: all angles and sides are different measurements.
f. acute
: all the three angles are acute (Less than 90)
Answer:
$412.92
Step-by-step explanation:
You are going to want to use the compound interest formula, which is shown below.
<em>P = initial balance
</em>
<em>r = interest rate
</em>
<em>n = number of times compounded annually
</em>
<em>t = time
</em>
<em />
The first step is to change 4% into its decimal form:
4% -> -> 0.04
Now plug in the values:
It would be worth $412.92
Answer:
a. dQ/dt = -kQ
b.
c. k = 0.178
d. Q = 1.063 mg
Step-by-step explanation:
a) Write a differential equation for the quantity Q of hydrocodone bitartrate in the body at time t, in hours, since the drug was fully absorbed.
Let Q be the quantity of drug left in the body.
Since the rate of decrease of the quantity of drug -dQ/dt is directly proportional to the quantity of drug left, Q then
-dQ/dt ∝ Q
-dQ/dt = kQ
dQ/dt = -kQ
This is the required differential equation.
b) Solve your differential equation, assuming that at the patient has just absorbed the full 9 mg dose of the drug.
with t = 0, Q(0) = 9 mg
dQ/dt = -kQ
separating the variables, we have
dQ/Q = -kdt
Integrating we have
∫dQ/Q = ∫-kdt
㏑Q = -kt + c
when t = 0, Q = 9
So,
c) Use the half-life to find the constant of proportionality k.
At half-life, Q = 9/2 = 4.5 mg and t = 3.9 hours
So,
taking natural logarithm of both sides, we have
d) How much of the 9 mg dose is still in the body after 12 hours?
Since k = 0.178,
when t = 12 hours,