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Colt1911 [192]
3 years ago
14

Which box plot correctly displays the data set with a maximum of 48, a minimum of 27, a median of 36, an upper quartile of 45, a

nd a lower quartile of 32?

Mathematics
2 answers:
Zarrin [17]3 years ago
3 0

The first box plot, the smallest data point is the minimum and the largest the maximum, the first line is the lower quartile, the middle line is the median, the third line is the upper quartile.

Andru [333]3 years ago
3 0

Answer:

Option 1 is correct

Step-by-step explanation:

Given that maximum is 48.  

Of the given four box plots only options 1 and 3 satisfy this. So we can ignore 2 and 4 as incorrect.

Comparing 1 and 2, let us find minimum. Minimum is both shown as 27.

I quartile, 32 is shown correctly in Option I.  But in Option III it is shown as 31.

Hence OPtion III is incorrect

The only option which shows minimum as 27, median 36, upper quartile 45 and lower quartile 32 is Option I.

Hence OPtion I is the only correct option

You might be interested in
if two angles of a triangle have measures of 42 degrees and 20 degrees what is the measure of the third
Mila [183]
Every triangle has an angle measure of 180 degrees.

so 42+20+x (where x is the measure of the third angle)=180

Combine like terms.

62+x=180

Subtract 62 from both sides

x=118.
3 0
3 years ago
Someone plz help me
topjm [15]

x = 375 and y = 6300. Option C.

Step-by-step explanation:

From the given data we need to find the value of x and y.

First, we will find out the ratio of area and the force.

\frac{Area}{Force}  = \frac{125}{1875} =\frac{150}{2250} =\frac{175}{2625} = \frac{1}{15}

So,

\frac{x}{5625} = \frac{1}{15}

or, x = \frac{5625}{15} = 375

Again,

\frac{420}{y} = \frac{1}{15}

or, y = 420×15 = 6300

Hence,

x = 375 and y = 6300.

7 0
3 years ago
How do you solve this problem K/2+9=30
bonufazy [111]
11 that is the answer
3 0
2 years ago
Read 2 more answers
An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume
Lynna [10]

Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0
2 years ago
Please help im so confused
MArishka [77]

Answer:

i

Step-by-step explanation:

i = \sqrt{-1}

i^2 = -1

i^3 = -i

i^4 = 1

(Make sure you know your exponent rules)

i^4^1 = i^4^0 * i = (i^1^0)^4 * i \\i^4 = 1 \\i^1^0 * i *1 \\i^1^0=1\\1*1*i=i

3 0
3 years ago
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