Motion and rate of change derivatives. Attached is the question and where I am stuck, I would really appreciate the help :)
1 answer:
Answer:
A. 3 < t < 9
Step-by-step explanation:
You have successfully found the values of t where the motion turns around (t=3 and t=10). Your knowledge of odd-degree polynomials tells you that the value of s(t) is decreasing for t < 3 (because the leading coefficient is negative), and is also decreasing for t > 10.
That is, the value of s(t) is increasing between t=3 and t=10, which means the particle is moving to the right in that interval. Since the function is only defined on the interval [0, 9] the particle is moving to the right on the interval (3, 9).
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At t=3 and t=10, the particle is stationary, moving neither right nor left.
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Answer:
see the explanation
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form or
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
Let
x ----> the time in hours
y ----> the distance in miles
<em>Find the value of k</em>
For the point (4,2268)
The slope represent the speed of the airplane
so
The linear equation is
Part 1 :
The point (0,0) represents the starting point of the aircraft, when the time and distance are equal to zero. The cruising starts when time t = 0.
Part 2 :
The point (4, 2268) represents the plane after 4 hours of cruise , and shows it has traveled a distance of 2268 miles after 4 hours
