All categories

3 years ago

Rectangle ABCD was dilated to create rectangle A'B'C'D.

Mathematics

2 answers:

77julia77 [94]3 years ago

8 0

The first thing we must do for this case is to calculate the scale factor.

For this, we make the relationship between two parallel sides.

We have then:

$k =\frac{B'C'}{BC}$

Substituting values we have:

$k = \frac{9.5}{3.8}\\k = 2.5$

We are now looking for the value of AB

We have then:

$AB = \frac{A'B'}{k}$

Substituting values:

$AB = \frac{15}{2.5}\\AB = 6$

Answer:

The scale factor is:

$k = 2.5$

The value of AB is:

$AB = 6$

DochEvi [55]3 years ago

4 0

AB is 6 units
Hope this helps

You might be interested in

the outdoor temperaturedeclines 3 degrees each hour for 5 hours. What is the change in temperature at the end of those 5 hours?

hodyreva [135]

15 degrees will be declined in the 5 hours.

3 0

3 years ago

The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds

boyakko [2]

The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation $h=-16t^2+24t+16$ , where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation $h=-16t^2+24t+16$ , we get,

$0=-16t^2+24t+16$

Switch sides, we have,

$-16 t^{2}+24 t+16=0$

Let us solve the equation using the quadratic formula.

Thus, we have,

$t=\frac{-24 \pm \sqrt{24^{2}-4(-16) 16}}{2(-16)}$

Simplifying, we get,

$t=\frac{-24 \pm \sqrt{576+1024}}{-32}$

$t=\frac{-24 \pm \sqrt{1600}}{-32}$

$t=\frac{-24 \pm 40}{-32}$

Hence, the two values of t are

$t=\frac{-24 + 40}{-32}$ and $t=\frac{-24 -40}{-32}$

Simplifying the values, we get,

$t=\frac{16}{-32}$ and $t=\frac{-64}{-32}$

Dividing, we get,

$t=-\frac{1}{2}$ and $t=2$

Since, t cannot negative values, we have,

$t=2$

Thus, the rock will hit the ground at 2 seconds.

8 0

3 years ago

A submarine is located 25 meters below sea level it goes up 7 meters then goes down 38 meters wrote plan integer to represent th

uranmaximum [27]

The question is somewhat confusing but assuming you mean where the submarine is after moving up 7 meters then down 38 meters the submarine would now be located 56 meters below sea level

7 0

3 years ago

How t f do I lable this I get so many of these and I've never been thought it

Naddika [18.5K]

Answer:

Label the y-axis Charms and the x-axis Beads

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

How do i solve the question in the image provided ?

Mars2501 [29]

Answer:

0.19+0.46i and 0.19-0.46i

Step-by-step explanation:

$\neq (-b+\sqrt{b^2-4ac} )/2a\\and\\(-b-\sqrt{b^2-4ac} )/2a\\\\a=8\\b=3\\c=2\\(-3+\sqrt{3^2-4*8*2} )/(2*8)\\= - 0.1875+0.463512i\\(-3-\sqrt{3^2-4*8*2} )/(2*8) = -0.1875-0.463512i$

hope its right

6 0

3 years ago