Question

Find the smallest power of 10 that will exceed M. Let M = 118,526.65902.

Answer 1

Answer:

The smallest power of 10 that will exceed $M$ is $10^{6}$.

Step-by-step explanation:

We can use the following approach to determine the smallest power of 10 that will exceed M. We can transform that number into scientific notation, which is of the form:

$x.y \times 10^{n}$, $\forall \,x,y\in \mathbb{N}$

Where:

$x$ - Integer part, formed by a digit, which is of the highest order.

$y$ - Decimal part, formed by a digit onwards.

$n$ - Power grade.

The smallest power of 10 that will exceed M is $10^{n+1}$

If $M = 118,526.65902$, then, the power grade is number of spaces that dot must be moved leftwards. In this case, dot must be moved 5 spaces on the left. The integer part is 1 and the decimal part is 1852665902. Then, the value of $M$ in scientific notation is:

$M = 1.1852665902\times 10^{5}$

Then, the smallest power of 10 that will exceed $M$ is $10^{6}$.