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Scilla [17]
4 years ago
8

Did anyone do the Algebra 1 interim assessment 2??? and can someone help me with it please!!!

Mathematics
2 answers:
vovangra [49]4 years ago
7 0
Use slader look up the book and see if it’s there
KATRIN_1 [288]4 years ago
3 0
For what school and just look up answers on brainly.
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Rewrite each of the following expressions without using absolute value bars.
Slav-nsk [51]

Answer:

A |x−4| if x>4

Step-by-step explanation:

8 0
2 years ago
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken to estimate
Hitman42 [59]

Answer:

The minimum sample size is n = 75 so that the desired margin of error is 5 or less.                          

Step-by-step explanation:

We are given the following in the question:

Population variance = 484

Standard deviation =

\sigma^2 = 484\\\sigma =\sqrt{484} = 22

Confidence level = 0.95

Significance level = 0.05

Margin of error = 5

Formula:

Margin of error =

E = z\times \dfrac{\sigma}{\sqrt{n}}\\\\n = (\dfrac{z\times \sigma}{E})^2

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get

E\leq 5\\\\1.96\times \dfrac{22}{\sqrt{n}} \leq 5\\\\\sqrt{n} \geq 1.96\times \dfrac{22}{5}\\\\n \geq (1.96\times \dfrac{22}{5})^2\\\\n \geq 74.373

Thus, the minimum sample size is n = 75 so that the desired margin of error is 5 or less.

3 0
3 years ago
.jh ip i pk ih ih i i pi ih ih hjk i i ihh k k
Aleonysh [2.5K]

Answer:

k k hhi i i kjh hi hi pi i i hi hi kp i pi hj

7 0
3 years ago
Read 2 more answers
I don’t know how to do this and my teacher doesn’t know how to teacher please help me
AnnyKZ [126]

Answer:

Yeah and i don't know how to answer that sorry

Step-by-step explanation:

you can't look it up some how?

8 0
3 years ago
-2|0.25-0.5 |+2=<br> What is this answer
Anestetic [448]

1.5

...

−2∣−0.25∣+2

−2×0.25+2

−0.5+2

8 0
3 years ago
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