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Scilla [17]
3 years ago
8

Did anyone do the Algebra 1 interim assessment 2??? and can someone help me with it please!!!

Mathematics
2 answers:
vovangra [49]3 years ago
7 0
Use slader look up the book and see if it’s there
KATRIN_1 [288]3 years ago
3 0
For what school and just look up answers on brainly.
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Solve for x PLS HELP NOW
Zepler [3.9K]

Answer:

x=70

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

<u />\frac{0.35}{\frac{2}{3}x } =\frac{0.45}{x-10}<u />

<u />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Cross-multiply:                    0.35(x-10)=\frac{2}{3} x \cdot 0.45
  2. Distribute 0.35:                   0.35x - 3.5=\frac{2}{3} x \cdot 0.45
  3. Multiply:                               0.35x - 3.5=0.3x
  4. Isolate <em>x</em> term:                     -3.5=-0.05x
  5. Isolate <em>x</em>:                              70=x
  6. Rewrite:                               x=70

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                   \frac{0.35}{\frac{2}{3}(70) } =\frac{0.45}{70-10}
  2. Multiply:                       \frac{0.35}{\frac{140}{3}  } =\frac{0.45}{70-10}
  3. Subtract:                      \frac{0.35}{\frac{140}{3}  } =\frac{0.45}{60}
  4. Evaluate:                     0.0075=0.0075
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