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tester [92]
3 years ago
13

(-9a? +12a - 10)+(9a? +10) I need help with this test

Mathematics
2 answers:
stiks02 [169]3 years ago
7 0
I think the answer would just be 12a because -9a? And +9a? Would cancel out and the -10 and +10 would cancel out so all that is left is the 12a
Nina [5.8K]3 years ago
7 0

Answer:

12a

Step-by-step explanation:

Because -9a and 9a would get rid of themselves the only "a-value" left is 12a. 10 and -10 also cancel each other out so 12a is all that is left.

If you need more help let me know, have a great day!

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Answer:

  a) j(t) = -16t^2 +20t +6

  b) 1 second

  c) less time

Step-by-step explanation:

The general equation for vertical motion is ...

  h(t)=-\dfrac{1}{2}gt^2+v_0t+h_0\\\text{where $v_0$ is the initial upward velocity, and $h_0$ is the initial height}

__

a) j(t) = -16t^2 +20t +6 . . . . . filling in the given initial values, with g=32 ft/s^2

__

b) We want to find the larger of the solutions to ...

  j(t) = 10 = -16t^2 +20t +6

Subtracting 6 and dividing by -4, we have ...

  -1 = 4t^2 -5t

  4t^2 -5t +1 = 0 . . . . add 1, put in standard form

  (4t -1)(t -1) = 0 . . . . . factor

  t = 1/4 or 1

The ball is in the air 1 second before reaching the hoop.

__

c) In generic terms, the equation of motion for a given shooting height at the same upward velocity will be ...

  10 = -16t^2 +20t + h0

  -16t^2 +20t +(h0 -10) = 0

Using the quadratic formula, we find the larger solution to be ...

  t = (-(20) -√(20² -4(-16)(h0 -10)))/(2(-16))

  t = (5/8) + √(64h0 -240)/32 = (5 +√(4h0 -15))/8

This value increases as h0 increases, so the ball will be in the air less time when Raymond shoots.

7 0
4 years ago
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