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AlladinOne [14]
3 years ago
15

What is the slope of the line containing the points (5,6) and (9,13)

Mathematics
2 answers:
Ann [662]3 years ago
4 0
Hello! You find the slope of the line by doing the formula y2 - y1 / x2 - x1. That means you subtract the first y-coordinate from the second y-coordinate and the first x-coordinate from the second x-coordinate. Plug in the values to get 13 - 6 / 9 - 5. Subtract the numbers to get 7/4. There. The slope of the line is 7/4.
Nataly_w [17]3 years ago
3 0
You would subtract the y intercepts then the x intercepts. Subtract 13-6 then divide it by 9-6. That gets you a slope of 7 over 3
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Answer:

A. Henry's balloon was farther from the town at the beginning, and it

traveled more quickly.

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1 year ago
Bacteria vary somewhat in size, but a diameter of 1.5 μ m is not unusual.
Dmitrij [34]

Answer:

a) 1.8 × 10^-12 cm³ or 1.8 × 10^-12 cubic meters

b) 7.1 × 10^-6 mm² or 7.1 × 10^-6 square millimeters

Step-by-step explanation:

a) We are assuming that the shape of the bacteria is a sphere.

Hence, Volume of the Sphere(Bacteria) = 4/3 × π × r³

Diameter = 1.5 μm

Radius = Diameter/2 = 1.5μm/2

= 0.75μm

We are told that the volume should be in cubic centimeters

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1 μm = 1 × 10^-4 cm

0.75 μm =

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= 0.75 μm × 1 × 10^-4 cm/ 1 μm

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= 4/3 × π × (0.000075)³

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b) The formula for the Surface area of a Sphere = 4πr²

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Radius = Diameter/2 = 1.5μm/2

= 0.75μm

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Converting 0.75μm to millimeters

1 μm = 0.001 mm

0.75 μm =

Cross Multiply

= 0.75 μm ×0.001mm/ 1 μm

= 0.00075mm

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= 7.06858 ×10^-6 mm²

Approximately to 2 significant figures

= 7.1 × 10^-6 mm²

6 0
3 years ago
I am a 2-digit number. The sum of my digits is 16. My ten’s digit is greater than my one’s digit. What number am I?
jarptica [38.1K]

Answer:

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8 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

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For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

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Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

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3 years ago
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