The size of the sample they should take to estimate p with a 2% margin of error and 90% confidence is n = 1691.
In statistics, the margin of error is just the degree of a significant error in the outcomes of random sample surveys.
The formula of margin error is, E = z√((p-vector)(1 - (p-vector)) ÷ n)
E = 2% = 0.02
Confidence level = 90%
Now, the proportion is not given so adopt nominal (p-vector) = 0.05
The critical value at CL of 90% is 1.645.
Thus, making n the subject,
n = z²(((p-vector) × (1 - (p-vector))) ÷ E²)
n = 1.645²((0.5 × 0.5) ÷ 0.02²)
n = 1691.266
n ≈ 1691
Read more about the margin of error at
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A. The discriminant is 81. The formula is b^2 - 4ac.
B. 2 answer and both will be rational due to the fact that the discriminant is a perfect square.
C. Solutions are 1/2 and -4. You can find using the quadratic formula.
Answer:
Solution given:
South distance :base[b]=80milea
East distance :perpendicular [p]=35miles
Now
<S=?
we have


=24°
24° bearing should be taken from south airport to East airport.
Answer:
The answers are
and
.
Step-by-step explanation:
Proportions are fractions that can be made by using the given numbers, which in this case are 2, 5, 8, and 20. Let's pair each one with the other three and then simplify if possible.
First, let's begin with 2:



Then, let's do 5:



Note that we already have
, so we do not need to include an additional one.
Now, let us do 8:



See how we already have
, so we won't have to include that as well.
Finally, let's do 20:



Now see that we already have both
and
, so we won't have to include both of them, as they are both extras.
Hence, the answers are
and
.
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