Answer:
Me neither. I feel your pain.
Step-by-step explanation:

Start with the standard form of a circle, where
is the center of the circle and
is the radius.

Plug in the known values.

This is the circle's equation in standard form.
Answer:
Step-by-step explanation:
F(x) = 2^x
64 = 2^x
2^6 = 2^x
x = 6
f(x) = 2^x
log (f(x)) = x log 2
x = log (f(x)) / log 2 = log_2 (f(x))
Therefore, the required logarithmic function is x = log_2 (f(x))
Click to let others know, how helpful is it
Answer:
R theta 1 = 20 x
R theta 2 = 11 x - 6
R ( theta 1 + theta 2) = 31 x - 6 adding equations
R pi = 31 x - 6 since theta 1 + theta 2 = 180 deg
x = (R pi + 6) / 31
This equation depends only R
If one lets R be one then x = (pi + 6) / 31
This would give x = .29489 rad for the value of pi is deg
The numerical value of x appears to depend on the value of R