This is the concept of trigonometry, to solve the question we proceed as follows;
sec(x)=1/cosx
thus;
sec(205)=1/cos205
=1/-0.9063
=-1.1034
this implies that:
sec(205)<-1
The mean is the average of a given data set and can be obtained by taking the sum of all numbers and dividing that by the amount of numbers in the data set.
58 + 43 + 33 + 69 + 41 + 74 = 318
There are 6 numbers in the data set.
318 / 6 = 53
(((1/y - 1) + (5/12)) = (-2/3y - 3))
((((1)(12)/12(y - 1) + (5(y + 1)/12(y + 1) = (-2/3y - 3))
((12/12y - 12) + (5y + 5/12y - 12)) = (-2/3y - 3))
((5y + 17/12y - 12) = (-2/3y - 3)
(12y - 12/5 + 17) × (5y + 17/12y - 12) = (-2/3y - 3)(12y - 2/5 + 17)
y = -21y + 4/66y - 66
y = -7/22 - 2/33
y = -25/66
T= 7/18 in fraction form
in expanded form its 144- 216t= 60
Alternate forms are 84 - 216t = 0 and -72 ( 3t - 2 = 60)
The result is 72 ( 2 - 3t) = 60
