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svlad2 [7]
2 years ago
14

I need help please I have to finish this

Mathematics
1 answer:
4vir4ik [10]2 years ago
6 0

Answer: x=4

Step-by-step explanation:

We know that line segment AC= AB + BC

we also know that AB= 3x+8 and BC= 2x-5

by substituting these, we get AC= (3x+8)+(2x-5)

AC is given as being 23, so we know that

23= (3x+8)+(2x-5)

by combining like terms, we get that

5x+3=23

simplify this to get that x=4

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A particle is moving with acceleration a ( t ) = 18 t + 16 . Its position at time t = 0 is s ( 0 ) = 10 and its velocity at time
MatroZZZ [7]

Answer:

s(8)=2186

Step-by-step explanation:

A particle is moving with acceleration modeled by the function:

a(t)=18t+16

We are given that its position s(t) at <em>t</em> = 0 is 10 and that its velocity v(t) at <em>t</em> = 0 is 16.

And we want to find its position at <em>t</em> = 8.

Velocity is the integral of the acceleration. Hence:

\displaystyle v(t)=\int a(t)\, dt=\int 18t+16\, dt

Find the velocity. Remember the constant of integration!

v(t)=9t^2+16t+C

Since v(t) is 16 when <em>t</em> = 0:

(16)=9(0)^2+16(0)+C\Rightarrow C=16

Hence, our velocity is given by:

v(t)=9t^2+16t+16

Position is the integral of the velocity. Hence:

\displaystyle s(t)=\int v(t)\, dt=\int 9t^2+16t+16\, dt

Integrate:

\displaystyle s(t)=3t^3+8t^2+16t+C

s(t) is 10 when <em>t</em> = 10. Hence:

C=10

So, our position function is:

s(t)=3t^3+8t^2+16t+10

The position at <em>t</em> = 8 will be:

s(8)=3(8)^3+8(8)^2+16(8)+10=2186

3 0
2 years ago
Zipora wants to construct a triangle that has the following angle measures: 50°, 75°, and 55°. How many triangles can she make?
Alborosie
As sum of all angles of triangle equal to 180 degrees.
First we have to add the angles.
50+75+55
=50+130
=180 degrees

Answer: Zipora can construct exactly one triangle.
4 0
3 years ago
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Please find the exact value of each trigonometric function
Lerok [7]
Mmm i don’t know sorry ok
7 0
2 years ago
PLZ HELP E!!!!!!! WILL MARK BRAINLIEST
vitfil [10]

Answer:

1

+

sec

2

(

x

)

sin

2

(

x

)

=

sec

2

(

x

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Start on the left side.

1

+

sec

2

(

x

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sin

2

(

x

)

Convert to sines and cosines.

Tap for more steps...

1

+

1

cos

2

(

x

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sin

2

(

x

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Write  

sin

2

(

x

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as a fraction with denominator  

1

.

1

+

1

cos

2

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x

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⋅

sin

2

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x

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1

Combine.

1

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cos

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x

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⋅

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Multiply  

sin

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x

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2

by  

1

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1

+

sin

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(

x

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cos

2

(

x

)

⋅

1

Multiply  

cos

(

x

)

2

by  

1

.

1

+

sin

2

(

x

)

cos

2

(

x

)

Apply Pythagorean identity in reverse.

1

+

1

−

cos

2

(

x

)

cos

2

(

x

)

Simplify.

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1

cos

2

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x

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Now consider the right side of the equation.

sec

2

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x

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1

2

cos

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x

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One to any power is one.

1

cos

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2 years ago
Find the area of the circle below. Use the formula <br> Use 3.14 for pi.
kirill [66]

Answer:

314

Step-by-step explanation:

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6 0
2 years ago
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