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svlad2 [7]
3 years ago
14

I need help please I have to finish this

Mathematics
1 answer:
4vir4ik [10]3 years ago
6 0

Answer: x=4

Step-by-step explanation:

We know that line segment AC= AB + BC

we also know that AB= 3x+8 and BC= 2x-5

by substituting these, we get AC= (3x+8)+(2x-5)

AC is given as being 23, so we know that

23= (3x+8)+(2x-5)

by combining like terms, we get that

5x+3=23

simplify this to get that x=4

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Simplify (x-3)(x^2+7x-8)
klio [65]
A common way to simplify this problem would be to use an area model, or the distributive property. Using the distributive property does not require any drawing, so here goes.
(x-3)(x²+7x-8)   Distribute by multiplying each of the terms in the first set of parentheses by every term in the second set of parentheses.
x³+7x³-8x-3x²-21x+24   Then combine alike terms.
8x³-3x²-29x+24    Is your final answer.
7 0
3 years ago
Can someone Help me please
Sonbull [250]

Answer:

Lower quartile= 4

Middle quartile= 6

Upper quartile=8

7 0
3 years ago
One thumbtack weighs 0.25 ounce. How many thumbtacks are in a box that has a mass of 3500 grams? (Hint: 1oz ~28g
Marina86 [1]
Alright so .25 oz is 1/4 of 1oz.  Therefore you take 28 and divide it by 4 and get 7.

Then take 3500 and divide it by 7 which makes 500 thumb tacks.

I think idk though.
7 0
4 years ago
Delta makes 12-volt car batteries. These batteries are known to be normally
blondinia [14]

Answer:

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the sample size n =12 -volt car batteries</em>

<em>Let  'X' be a Random variable in a normal distribution</em>

<em>Given that mean of the normal distribution = 45 months</em>

<em>Given that the Standard deviation of the normal distribution = 8months</em>

<u><em>Step(ii):-</em></u>

Let  X₁ = 3 years = 12 × 3 = 36 months

Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{36-45}{8} = -1.125

Let X₂ = 4 years  = 12 × 4 = 48 months

Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{48-45}{8} = 0.375

<u><em>Step(iii)</em></u>:-

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = P(-1.125≤Z≤0.375)

                   = P(Z≤0.375) - P(Z≤-1.125)

                   = 0.5 +A(0.375) - (0.5-A(1.125)

                   = 0.5 + 0.1480 - (0.5 -0.3708)

                  = 0.1480 + 0.3708

                 = 0.5188

<u><em>Final answer:-</em></u>

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

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5 0
3 years ago
I NEED HELP PLEASE 30 points
kenny6666 [7]
(2, 4) is the correct answer
8 0
4 years ago
Read 2 more answers
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