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2 years ago

A. Cumberland And Lincoln B.lincoln and ocean C.Lincoln and summit D.Ocean and Summit

Mathematics

1 answer:

amm18122 years ago

5 0

Ocean and Summit charge the same penalty per week.

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What is the solution of the system? Use substitution.

trasher [3.6K]

4x-y=5

3x-7=2

We need to solve 3x-7=2 for x

Let's start by adding 7 to both sides

3x-7+7=2+7

3x=9

Now just divide both sides by 3 so we can find the value for x

3x/3=9/3

x=3

Now substitute 3 for x in 4x-y=5

4x-y=5

(4)(3)-y=5

-y+12=5

Now add -12

-y=12-12=5-12

-y=-7

Divide both sides by -1 so we can eliminate the negative sign

-y/-1=-7/-1

y=3

The answer is A

(3,7)

I hope that's help:0

6 0

3 years ago

Whoever can help me with my math i will mark brainliest

mezya [45]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the surface area of the square pyramid 8mm 6mm

bija089 [108]

Answer:

136 mm²

Step-by-step explanation:

$A=a^{2} +2a\sqrt{\frac{a^{2} }{4} } +h^{2}$

$A=6^{2} +2(6)\sqrt{\frac{6^{2} }{4} } +8^{2}$

$A=36 +12\sqrt{\frac{36 }{4} } +64$

$A=36 +12\sqrt{9 } +64$

$A=36 +12(3)+64$

$A=36 +36+64$

A = 136

5 0

2 years ago

A researcher is going to estimate the average typing speed of students of a college. He selects a random sample of 20 students a

Stella [2.4K]

Answer:

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 1.7291

The margin of error is:

$M = T\frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have $s = 5, n = 20$ . So

$M = T\frac{s}{\sqrt{n}}$

$M = 1.7291\frac{5}{\sqrt{20}}$

$M = 1.933$

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

8 0

3 years ago

Distance time speed<br>

OLEGan [10]

Speed = Distance ÷ Time

3 0

2 years ago