I believe the answer is C.
Answer:
customers += newCustomer;
Explanation:
The operator += expands into + and assignment. The assignment is not overloaded so the required code is
customers += newCustomer;
This expands into
customers = customers + newCustomer;
The overloaded + operator is called for the right expression. This returns a `CustomerList`, which is then assigned through the = operator to `customers`.
<span>When an electric current flows through a long conductor, each free electron moves </span>one end to the other end depending upon the resistance and voltage drop.
