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3 years ago

The range of the function f(x) = x + 5 is {7, 9}. What is the function’s domain?

Mathematics

1 answer:

adoni [48]3 years ago

4 0

The domain for a linear function is always ¨all real numbers.¨

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Prove that the expression (y+8)(y-7)-y(y+1) is negative for any value of y

Anna71 [15]

Answer:

-56

Step-by-step explanation:

=(y)(y)+(y)(−7)+(8)(y)+(8)(−7)+−y2+−y

=y2+−7y+8y+−56+−y2+−y

=(y2+−y2)+(−7y+8y+−y)+(−56)

5 0

3 years ago

I might be going crazy but I dont think any of these work? Please help

ipn [44]

Answer:

That's strange. (-1/2, 5) would work for both if only the top equation had a less than or equal to sign. If all else fails, just puts c as your answer lol

Step-by-step explanation:

8 0

3 years ago

Which expression can be used to model the phrase “the sum of three and a number”? 3+x x-3

natima [27]

A=3+b. That is a reasonable expression, because a= the sum of 3 and b, an unknown number.

6 0

4 years ago

Read 2 more answers

Write as an expression and simplify

Alexus [3.1K]

Answer:

Part a) $(2m+7n)(2m-7n)$

Part b) $x^2-16xy+64y^2$

Part c) $216a^3b^6$

Part d) $(a^2-b^2)$

Step-by-step explanation:

Part a) The difference of the squares of 2m and 7n.

we know that

The difference of the squares formula is equal to

$(a^2-b^2)=(a+b)(a-b)$

substitute

$(2m)^2-(7n)^2=(2m+7n)(2m-7n)$

Part b) The square of the difference of x and 8y

The formula of the square of the difference between two numbers is equal to

$(a-b)^2=a^2-2ab+b^2$

substitute

$(x-8y)^2=x^2-2(x)(8y)+(8y)^2=x^2-16xy+64y^2$

Part c) The tripled product of 6a and b^2

we have

$(6ab^{2})(6ab^{2})(6ab^{2})=(6ab^{2})^3=(6^3)(a^3)(b^{2})^3=216a^3b^6$

Part d) The product of the sum of a and b and their difference

The expression is equal to

$(a+b)(a-b)$

The expression represent the difference of the squares between a and b

$(a+b)(a-b)=(a^2-b^2)$

7 0

3 years ago

Read the description of g below, and then use the drop-down menus to complete an explanation of why g is or is not a function. g

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Domain: Students enrolled in a school year

Range: The english course a students takes

g is a function because each student, or each element of the domain, corresponds to one element of the range

3 0

4 years ago