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zlopas [31]
3 years ago
8

Write as an expression and simplify

Mathematics
1 answer:
Alexus [3.1K]3 years ago
7 0

Answer:

Part a) (2m+7n)(2m-7n)

Part b) x^2-16xy+64y^2

Part c) 216a^3b^6

Part d)  (a^2-b^2)

Step-by-step explanation:

Part a) The difference of the squares of 2m and 7n.

we know that

The difference of the squares formula is equal to

(a^2-b^2)=(a+b)(a-b)

substitute

(2m)^2-(7n)^2=(2m+7n)(2m-7n)

Part b) The square of the difference of x and 8y

The formula of the square of the difference between two numbers is equal to

(a-b)^2=a^2-2ab+b^2

substitute

(x-8y)^2=x^2-2(x)(8y)+(8y)^2=x^2-16xy+64y^2

Part c) The tripled product of 6a and b^2

we have

(6ab^{2})(6ab^{2})(6ab^{2})=(6ab^{2})^3=(6^3)(a^3)(b^{2})^3=216a^3b^6

Part d) The product of the sum of a and b and their difference

The expression is equal to

(a+b)(a-b)

The expression represent the difference of the squares between a and b

so

(a+b)(a-b)=(a^2-b^2)

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Factor 18v⁹+33v⁸+14v⁷ completely ​
marin [14]

Answer:

v^{7} x (6v+7) x (3v+2)

Step-by-step explanation:

18v^9 + 33v^8 +14v^7

Factor out v^7 from the expression

v^7 x (18v^2+33v+14)

write 33v as a sum

v^7 x (18v^2+21v+12v+14)                  *like this 21v+12v

Factor out 3v from the expression

v^7 x (3v x (6v+7)+12v+14)

Factor out 2 from the expression

c^7 x (3v x (6v+7)+2(6v+7)

Factor out 6v+7 from the expression

v^7 x (6v+7) x (3v+2)

8 0
3 years ago
Money Flow An investment scheme is expected to produce a continuous flow of money, starting at $1000 and increasing exponentiall
kvasek [131]

Answer:

7.14

Step-by-step explanation:

3 0
3 years ago
Is 3 kg equal to 6 lbs? please i nned the answer for a math exam thank you
suter [353]
It’s equal to 6.614 pounds.
6 0
3 years ago
Read 2 more answers
15 is 30% of what number?
dangina [55]
#1---> let the number you are trying to find be x for the following questions

30%*x=15
x=15/30%
x=50

#2
10%*x=14
x=14/10%
x=140

#3
(4/32)*100
 is the same as (1/8)*100= 12.5%

#4
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5 0
3 years ago
Determine the values of a for which the following system of linear equations has no solutions, a unique solution, or infinitely
navik [9.2K]

Answer:

Never

Never

Never

Step-by-step explanation:

The equations given are

2x1−6x2−4x3 = 6 ....... (1)

−x1+ax2+4x3 = −1 ........(2)

2x1−5x2−2x3 = 9 ..........(3)

the values of a for which the system of linear equations has no solutions

Let first add equation 1 and 2. Also equation 2 and 3. This will result to

X1 + (a X2 - 6X2) - 0 = 5

And

X1 + (aX2-5X2) + 2X3 = 8

Since X2 and X3 can't be cancelled out, we conclude that the value of a is never.

a unique solution,

Let first add equation 1 and 2. Also equation 2 and 3. This will result to

X1 + (a X2 - 6X2) - 0 = 5

And

X1 + (aX2-5X2) + 2X3 = 8

The value of a = never

infinitely many solutions. 

Divide equation 1 by 2 we will get

X1 - 3X2 - 2X3 =3

Add the above equation with equation 3. This will result to

3X1 - 8X2 - 4X3 = 12

Everything ought to be the same. Since they're not.

Value of a = never.

4 0
3 years ago
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