Answer:
x (6v+7) x (3v+2)
Step-by-step explanation:
18v^9 + 33v^8 +14v^7
Factor out v^7 from the expression
v^7 x (18v^2+33v+14)
write 33v as a sum
v^7 x (18v^2+21v+12v+14) *like this 21v+12v
Factor out 3v from the expression
v^7 x (3v x (6v+7)+12v+14)
Factor out 2 from the expression
c^7 x (3v x (6v+7)+2(6v+7)
Factor out 6v+7 from the expression
v^7 x (6v+7) x (3v+2)
#1---> let the number you are trying to find be x for the following questions
30%*x=15
x=15/30%
x=50
#2
10%*x=14
x=14/10%
x=140
#3
(4/32)*100
is the same as (1/8)*100= 12.5%
#4
1%* x=11
x=11/1%
x=1100
by the way * means multiply
Answer:
Never
Never
Never
Step-by-step explanation:
The equations given are
2x1−6x2−4x3 = 6 ....... (1)
−x1+ax2+4x3 = −1 ........(2)
2x1−5x2−2x3 = 9 ..........(3)
the values of a for which the system of linear equations has no solutions
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
Since X2 and X3 can't be cancelled out, we conclude that the value of a is never.
a unique solution,
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
The value of a = never
infinitely many solutions.
Divide equation 1 by 2 we will get
X1 - 3X2 - 2X3 =3
Add the above equation with equation 3. This will result to
3X1 - 8X2 - 4X3 = 12
Everything ought to be the same. Since they're not.
Value of a = never.