The correct answer is that there is more variability in the heights of the volleyball team members.
The mean absolute deviation shows us how spread out the data is, so the larger the mean absolute deviation the higher the variability.
Both teams have players that are 76 inches tall, so the last two statements cannot be true.
Answer:
x>3
Hope this helps!
The poopulation exponential model is given by

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.
Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

Thus, the exponential equation using the 1750 and the 1800 population values is

The population of 1900 using the 1750 and the 1800 population values is given by

The population of 1950 using the 1750 and the 1800 population values is given by

From the table, it can be seen that the actual figure is greater than the exponential model values.
Answer: f(7)=f(1)+4
Step-by-step explanation: