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iVinArrow [24]
3 years ago
13

Please please help me! all you smart math people please give me a hand​

Mathematics
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

Step-by-step explanation:

...;3

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Can someone please help me with math???
arlik [135]

Answers:

2x + 7

2x - 7 = 14

2 + 7

4 0
3 years ago
Im Triggered Pls Dont DELETE!
stepladder [879]

I'm assuming you mean f(x) = (e^x + 5x)^2, not f(x) = (e x + 5x)2, like your prompt suggests.


First, let's figure out what rule we can use. A likely noticeable one is the Power Rule, which says the following:

\dfrac{d}{dx} [u^a] = a(u)^{a-1} du


Applying this, we can solve for the derivative:

f'(x) = 2(e^x + 5x) (e^x + 5)

  • Apply the Power Rule

While you can simplify the expression to your liking, I believe that this form is not overly complex and will thus leave it as is.


Thus, our answer is:

f'(x) = \boxed{2 (e^x + 5x)(e^x + 5)}

7 0
3 years ago
Read 2 more answers
1 + 2b – 13 = 12 – 4b – 2b for b
Marysya12 [62]
The answer is b=3 for your problem
6 0
3 years ago
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I NEED HELP PLEASE HELP. SHOW ME HOW YOU DID IT
victus00 [196]
Sin = - 4/8

Quadrant IV = only cosine is positive

a = height (4)
b = base ( 8^2-4^2=b^2
b = 6.93 @
\sqrt{48}

c = hypothenuse(8)

cos =
\sqrt{48}
/8

tan = - 4/
\sqrt{48}

sec = 1/cos
1/cos = 1/ (
\sqrt{48}
/8)
sec = 8/
\sqrt{48}

csc = 1/sin
1/sin = 1/(-4/8)
csc = - 2

cot = 1/tan
1/tan = 1/(-4/
\sqrt{48}
)
cot = -
\sqrt{48}
/4

5 0
3 years ago
The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviat
nexus9112 [7]

Answer:

Two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

Step-by-step explanation:

We are given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviation of 0.07 millimeters.

<em>Let X = diameters of bolts produced in a machine shop</em>

So, X ~ N(\mu=5.65,\sigma^{2} = 0.07^{2})

The z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean

            \sigma = standard deviation

<u>Now, we have to find the two diameters that separate the top 4% and the bottom 4%.</u>

  • Firstly, Probability that the diameter separate the top 4% is given by;

        P(X > x) = 0.04

        P( \frac{X-\mu}{\sigma} > \frac{x-5.65}{0.07} ) = 0.04

        P(Z > \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the top 4% is given as 1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = 1.7507

              x-5.65 = 0.07 \times 1.7507

                         x = 5.65 + 0.122549 = 5.77

  • Secondly, Probability that the diameter separate the bottom 4% is given by;

        P(X < x) = 0.04

        P( \frac{X-\mu}{\sigma} < \frac{x-5.65}{0.07} ) = 0.04

        P(Z < \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the bottom 4% is given as -1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = -1.7507

              x-5.65 = 0.07 \times (-1.7507)

                         x = 5.65 - 0.122549 = 5.53

Therefore, the two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

4 0
3 years ago
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