Answer:
I'm going to do it but you should try these things for yourself or else you won't learn.
Explanation:
-First create a project (I'm using Netbeans 14 and the project is a Maven, but the code should work on any IDE)
-Name the project 'ShoppingCartPrinter' and leave the package name as it is. This is the main class so the main method is gonna be there already.
-Then you will create a second class named 'ItemToPurchase'. So I'll leave the code in the attachment (at the bottom of my answer it's written 'Download txt') or else brainly will think it's some sort of redirection to another websites because of the 'dots' and won't let me post it.
Answer:
<em>The programming language in Python is as follows:-</em>
#Prompt user for input string
userinput = input("Enter a string: ")
#Print the last character of the input
print("The last character is "+userinput[-1])
#End of Program
Explanation:
This line is a comment
#Prompt user for input string
This line prompts user for input
userinput = input("Enter a string: ")
This line is also a comment
#Print the last character of the input
This next line prints the last character of the input string; the last character is defined by the index -1
print("The last character is "+userinput[-1])
Answer:
The above given statement is a fact.
Explanation:
A fact is nothing but a real statement which can never be false or imaginary or told in a future perspective. Let us analyze other options
Option 2: Opinion => An opinion can be anything and it can differ. A opinion is the way one people understand or perceive and give a statement according to that. An opinion always differs.
Option 3: Graphic => This is computer generated file, which can be true or false or imaginary. So this option is invalid
Option 4: Text => A text is nothing but words written together to convey a meaning. Though we feel like it suits the question, since the question speaks about the place, then it must definitely be fact and not just text.
Answer:
Question is incomplete.
Assuming the below info to complete the question
You have a collection of n lockboxes and m gold keys. Each key unlocks at most one box. Without a matching key, the only way to open a box is to smash it with a hammer. Your baby brother has locked all your keys inside the boxes! Luckily, you know which keys (if any) are inside each box.
Detailed answer is written in explanation field.
Explanation:
We have to find the reachability using the directed graph G = (V, E)
In this V are boxes are considered to be non empty and it may contain key.
Edges E will have keys .
G will have directed edge b1b2 if in-case box b1 will have key to box b2 and box b1 contains one key in it.
Suppose if a key opens empty box or doesn’t contain useful key means can’t open anything , then it doesn’t belongs to any edge.
Now, If baby brother has chosen box B, then we have to estimate for other boxes reachability from B in Graph G.
If and only if all other boxes have directed path from box B then just by smashing box B we can get the key to box b1 till last box and we can unlock those.
After first search from B we can start marking all other vertex of graph G.
So algorithm will be O ( V +E ) = O (n+m) time.
