Answer:
t = (D/C - 1) (100/r)
Step-by-step explanation:
D = C(1+rt/100)
D/C = 1 + rt/100
D/C - 1 = rt/100
D/C - 1 = t (r/100)
Therfore,
<h2>t = (D/C - 1) / r/100</h2>
Therefore the last option is correct.
<h2><em><u>
PLEASE MARK MY ANSWER AS BRAINLIEST!!!!!</u></em></h2>
The answer is definitely a
A single die is rolled twice. the set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
Maksim231197 [3]
<span>We need to find the rolls whose sum is greater than 10. By looking at the outcomes, we see that (5,6), (6,5), and (6,6) all have a sum greater than 10. Therefore, there are 3 chances to get a sum greater than 10. Since there are 36 chances overall, the probability of rolling greater than 10 are 3/36 = 1/12.</span>
