Answer:
this question is missing needed information
Answer: Time at which the meet = 10:17:24 am
Step-by-step explanation: Speed of Ivan = 12 mph
Speed of Kate = 16 mph
Total distance traveled = Initial separation = 40 miles
Ivan leaves his house at 8:00 a.m and Kate leaves her house at 9:30 a.m
If t is the time of catch up after Ivan starting, time taken by Kate is t - 1.5,
We have
Distance = Speed x Time
Total distance traveled = Distance traveled by Kate + Distance traveled by Ivan
40 = t x 12 + (t-1.5) x 16
40 = 28t - 24
28t = 64
t = 2.29 hours
So after 2.29 hours of Ivan's starting they meet,
Time = 8:00 am + 2.29 hours = 10:00 am + 0.29 x 60 minutes = 10:17am + 0.4 x 60 seconds = 10:17:24 am
Time at which the meet = 10:17:24 am
A problem with extra information will be difficult to solve because you may not be able to tell what information you might need to use for the problem.
Area = b*h and in some cases * 2 so you need to do this, 64*52 + 40*28= 4448 yd2
