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2 years ago

1) radius = 2 feet height = 4 feet

Mathematics

2 answers:

LekaFEV [45]2 years ago

8 0

Answer:

R=2

Step-by-step explanation:

2x2=4

Serjik [45]2 years ago

8 0

Hope this helps
r=2
2times2 equal 4

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Write the expression in complete factored form. 4c(y+3) - (y+3)=

Anuta_ua [19.1K]

Answer:

(4c-1)(y+3)

Step-by-step explanation:

4c(y+3) -(y+3)

=(4c-1)(y+3)

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2 years ago

Please help I need work shown!!

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3x-11=2x+11

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2 years ago

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Find the value of A if A=1\2bh, b=8 and h= 9

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2 years ago

Find all solutions to the equation. 2sin theta - squareroot 3 = 0

Xelga [282]

Answer:

$\theta$ =2mπ + π/3 for m ∈ Z.

Step-by-step explanation:

Given the equation $2sin\theta - \sqrt{3} = 0$ , we are to find all the values of $\theta$ that satisfies the equation.

$2sin\theta - \sqrt{3} = 0\\\\2sin\theta = \sqrt{3} \\\\sin\theta = \sqrt{3}/2 \\\\\theta = sin{-1} \sqrt{3}/2 \\\\\theta = 60^0$

General solution for sin $\theta$ is $\theta$ = nπ + (-1)ⁿ ∝, where n ∈ Z.

If n is an even number say 2m, then $\theta$ = (2m)π + ∝ where ∝ = 60° = π/3

Hence, the general solution to the equation will be $\theta$ = 2mπ + π/3 for m ∈ Z.

8 0

2 years ago

Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq

AnnyKZ [126]

Answer:

$(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Step-by-step explanation:

Step(i):-

Given that the function

f(x) = $e^{4x} \sqrt{1+e^{2x} }$

Now integrating on both sides, we get

$\int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx$

= $\int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx$

Step(ii):-

Let $1 + e^{2x} = t$

$e^{2x} = t -1$

$2e^{2x}dx = d t$

$e^{2x}dx = \frac{1}{2} d t$

= $\int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx$

= $\int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }$

= $\frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }$

= $\frac{1}{2} \int\limits {(t^{\frac{1}{2} } t^{1} +t^{\frac{1}{2} } ) } \, dx$

$= \frac{1}{2} \int\limits {(t^{\frac{3}{2} } +t^{\frac{1}{2} } ) } \, dx$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C$

= $\frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C$

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Final answer:-

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

3 0

2 years ago