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lbvjy [14]
3 years ago
15

In 1998 the World Health Organization reported the findings of a major study on the quality of blood pressure monitoring around

the world. In its report it stated that for Canada the results for diastolic blood pressure had a mean of 78 mmHg and a standard deviation of 11 mmHg. Assuming that diastolic blood pressure measurements are Normally distributed, the DBP reading that represents the 80th percentile of the distribution is _____.
Mathematics
1 answer:
tresset_1 [31]3 years ago
7 0

Answer:

87.26 mm Hg is the reading that represents the 80th percentile of the distribution.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 78 mm Hg

Standard Deviation, σ = 11 mm Hg

We are given that the distribution of diastolic blood pressure is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.80

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 78}{11})=0.8  

Calculation the value from standard normal z table, we have,  

P(z < 0.842) = 0.8

\displaystyle\dfrac{x - 78}{11} = 0.842\\\\x = 87.262 \approx 87.26

87.26 mm Hg is the reading that represents the 80th percentile of the distribution.

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The Two Column Proof is given below.

Step-by-step explanation:

Given:

\overline{MP} \cong \overline{MN}

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1. MP ≅ MN                                   1. Given

2. PO ≅ NO                                  2. Given

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4. ΔMPO ≅ ΔMNO                       4. Side-Side-Side congruence test}

5. ∠MPO ≅∠MNO                        5. Corresponding parts of congruent Triangles

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