Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.
Using algebraic equations, the number of points Yael has is calculated as: 29 points.
<h3>How to Use Algebraic Equations to Solve Word Problems?</h3>
In the given world problem, we known the following:
E = Eric
S = Shenna
Y = Yael
Their total points would be: E + S + Y = 68
S = 2(E) (Shenna has twice the points of Erik)
Y = S + 3 (Yael has three points more than Shenna)
We would therefore have the following algebraic equation:
E + 2E + (S + 3) = 68
Substitute S with 2E
E + 2E + 2E + 3 = 68
Solve for E
5E + 3 = 68
5E = 68 - 3
5E = 65
5E/5 = 65/5
E = 13
Eric's points is: 13
Yael's points = Y = S + 3
Y = S + 3 = 2E + 3
Plug in the value of E
Y = 2(13) + 3
Y = 26 + 3
Y = 29
Yael has 29 points.
Learn more about algebraic equation on:
brainly.com/question/2164351
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Answer:
30
Step-by-step explanation:
boys: girls : total
3 7 3+7 =10
The total number of students must be a multiple of 10
The class size is between 22 and 34
The only multiple of 10 between those numbers is 30
10,20,<u>30</u>,40
Therefor the class size must be 30
Answer:
3%
Step-by-step explanation:
I = Prt
I = 1020
P = 8500
t = 4
1020 = (8500)(4)r
1020 = 34000r
r = 0.03
