It opens upward and the vertex is (2,-6) here are some plotted points: (0,6),(1,-3),(2,-6),(3,-3),(4,6). Hope that helps. I hate graphing but if you do it enough times you'll get the hang of it!
Answer:
Option (C) and (D)
Step-by-step explanation:
Given piecewise function is,
f(x) = 2x, x < 1
5, x = 1
, x > 1
Option (A),
x = 5 means x > 1
So the function will be,
f(x) = 
f(5) = (5)²
= 25
Therefore, f(5) = 1 is not correct.
Option (B),
x = -2 means x < 1
f(x) = 2x will be applicable.
f(-2) = 2(-2) = -4
Therefore, f(-2) = 4 is not correct.
Option (C)
For x = 1,
f(1) = 5
Therefore, f(1) = 5 is the correct option.
Option (D)
x = 2 means x > 1 and the function defined will be,
f(x) = x²
f(2) = 2²
= 4
Therefore, f(2) = 4 will be the correct option.
Options (C) and (D) will be the answer.
Answer:

Step-by-step explanation:
Given a circle centre J
Let the radius of the circle =r
LK is tangent to circle J at point K
From the diagram attached
Theorem: The angle between a tangent and a radius is 90 degrees.
By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.
Using Pythagoras Theorem:

The length of the radius, 
Angle a is directly opposite from a 40 degree angle, so a=40. Then we can find b since the sum of the angles of all triangles is 180 and there is a right angle in there along with angle a:


Last, to find c we just notice that it is supplementary with an angle of measure 65, so:


So our angles are a=40, b=50, c=115.