Answer: width is 9 , 13×8=104, 936/104=9
Check it 13×8×9=936
Answer:
$690.86
Step-by-step explanation:
100% from the original cost is: 2 x 863.57 = $1,727.14
40/100 = X/1727.14 (40 percent is what of 1,727.40) (%/100 = is/of)
(40 * 1,727.14) / 100 = $ 690.86
The complete question in the attached figure
Part A) How much sand is currently in the container?
[sand currently in the container]=(5)*(4 1/2)*(2.25)-----> (5)*(4.5)*(2.25)
[sand currently in the container]=50.625 in³
the answer Part a) is 50.625 in³Part B) How much more sand could the container hold before?
[sand could the container hold before]=[5*4.5*3]-[50.625]
[sand could the container hold before]=[67.5]-[50.625]------> 16.875 in³
the answer Part B) is 16.875 in³
Part C) What percent of the container is filled with sand?
the volume of container is [5*4.5*3]=67.5 in³
the volume filled with sand=50.625 in³
therefore
if 100%----------------> 67.5 in³
X---------------------> 50.625 in³
X=(50.625*100)/67.5=75 %
the answer Part C) is 75%
–2x<span> + 6. (</span>f<span> – </span>g)(x<span>) = </span>f<span> (</span>x<span>) – </span>g(x). = [3x + 2] – [4 – 5x]. = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x – 2. (f<span> × </span>g)(x) = [f<span> (</span>x)][g(x)]. = (3x + 2)(4 – 5x). = 12x + 8 – 15x2<span> – 10x ... of the </span>functions<span> at </span>x<span> = 2 and then work from there. It's probably simpler in this case to evaluate first, so: </span>f<span> (2) = 2(2) = 4. </span>g(2) = (2) + 4 = 6. h(2) = 5<span> – (2)</span>3<span> = 5 – 8 = –</span><span>3</span>
Answer:
22
Step-by-step explanation:
Let X be the time for only a small drain, the work completed would be unity.
The small drain has been open for a total of 11 hours, one hour next to the large one, and 10 hours alone.
We have that large drainage can accomplish this in 2 hours.
We have the following system:
1/2 + 11 / x = 1
solving, we have:
11 / x = 1 - 1/2
11 / x = 1/2
x = 11 * 2
x = 22
I mean it would take a total of 22 hours for the small drain alone