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3 years ago

Decide which of the two points lies on the graph of the line

Mathematics

1 answer:

Bezzdna [24]3 years ago

3 0

A, -1, -1 is your answer

6(-1) - 2(-1) = -4

-6 + 2 = -4

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If you have 18 students and all are paired up at least once how many projects in the year

KatRina [158]

It would be 9 because you get half the number of projects because 18 students are partners and if you divide that you would have 9 groups of 2 and if you multiply that by the number of projects you would get the number of projects (ex:18 dividend by 2 it's 9 then if there is three projects assigned you multiply 9 by 3 to get 27 projects got it?

4 0

3 years ago

Read 2 more answers

A rectangular piece of plastic has an area of 10 square millimeters and a perimeter of 22 millimeters. What are the dimensions o

storchak [24]

The piece of plastic have dinmensions of 1mm by 10mm

5 0

3 years ago

F(x)= 2x^3 + 5x^2 -x -6 is divided by x+1

eimsori [14]

Step-by-step explanation:

substitute x= -1 into the equation to get the remainder

remainder= -2

the remainder is not a fraction

no, it is not a factor since its remainder is not zero

8 0

2 years ago

An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov

babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this. This will give us the two times that the object is at exactly 500 meters. The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using our values for a, b and c,

$x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656$

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds. This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0

3 years ago

A coin is flipped, and a number cube is rolled. What is the probability of getting heads on the coin and a number greater than 5

Art [367]

Answer:

1/3

Step-by-step explanation:

3 0

2 years ago