They did not believe everything could be forgiven and fixed.
Answer:
it can contribute to headaches and high blood pressure
Allele frequency is used to display the genetic diversity of a species population .
Explanation:
To calculate the frequency of the recessive allele we use the
THardy-Weinberg equation
p² + 2pq + q²
p+q=1
p is the frequency of the homozygous dominant genotype
q is the frequency of the homozygous recessive genotype
2pq is the frequency of the heterozygous genotype.
Total number of individuals = 45 + 30+ 25 = 100
So, the frequency of recessive trait = 25/100 =0.25.
Thus, the value of q² = 0.25
So, q would be equal to square root of 0.25 which comes out to be 0.5
Answer:
There is no chance that a child of one parent who carries CF gene is born having Cystic Fibrosis if the other parent does not carry the CF gene.
Explanation:
Second child born to Chloe’s mother and stepfather will have Cystic Fibrosis only if they inherit one CF gene from each parent. Since stepfather is not carrier of CF gene, development of the disease at child is not possible.
A person who has inherited one CF gene from his/her parent will be a CF gene carrier, but will never develop Cystic Fibrosis. However as he/she a carrier of the CF gene, they can pass it on to their own child.
