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3 years ago

Isosceles triangle XYZ with angle X congruent angle Z? How do you construct?

Mathematics

1 answer:

KIM [24]3 years ago

8 0

Answer:

The construction is given below.

Step-by-step explanation:

we have to construct an isosceles triangle XYZ with angle X congruent angle Z. The steps of construction are

Step 1 : Construct a segment of any length XZ.

Step 2 : Adjust the compass such that it is greater than half of the segment and then put the needle of compass once at point X and then point Z and draw arc from both points.

Step 3 : Draw the segments from the two endpoints X and Z to the point where the two arcs intersect i.e at point Y.

By above steps of construction Isosceles triangle XYZ with angle X congruent angle Z is constructed.

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Help me with #5 pleaseeeeeeeeeee

earnstyle [38]

Answer:

$\angle 1 = 45$ degrees

Step-by-step explanation:

Sum of 3 angles in a triangle is 180..

The angles given are:

7x + 12

So we sum to 180 and write:

$60+7x+12+\angle 1=180\\72+7x+\angle 1=180\\7x+\angle 1=108$

Also, straight angle is 180 degrees, thus Angle 1 and (14x + 9) angle is sum to 180, thus we can write:

$14x+9+\angle 1=180\\14x + \angle 1=171$

Or we can write this as:

$14x + \angle 1=171\\\angle 1 = 171 - 14x$

We substitute this expression for Angle 1 into 1st equation we got and solve for x first,

$7x+\angle 1 = 108\\7x+( 171 - 14x)=108\\-7x=-63\\x=9$

Since x = 9, the angle "14x + 9" would be:

14(9) + 9 = 135

Hence Angle 1 would be:

$\angle 1 + 14x + 9 = 180\\\angle 1 + 135 = 180\\\angle 1 = 45$

6 0

2 years ago

Pls I need help this

Citrus2011 [14]

Answer:

the third side is 4.

Step-by-step explanation:

Using Pythagorean theorem of a^2 + b^2 = c^2 for right triangles, substitute

the numbers to show ( $\sqrt{65})^{2}$ + $b^{2}$ = $9^{2}$ and solve for b. The square root and square cancel each other out, so you get 65 + $b^{2}$ = 81.

Subtract 65 from both sides to get $b^{2}$ = 16.

Then take the square root of both sides to get b = $\sqrt{16}$ which equals 4.

6 0

3 years ago

Simplify sin^2y/sec^2 y−1 to a single trigonometric function

liubo4ka [24]

Answer:

$\frac{ { \sin}^{2} y}{ { \sec}^{2}y - 1 } = { \cos }^{2} y$

Step-by-step explanation:

We know that ${ \tan }^{2} y = { \sec }^{2} y - 1$

Also , ${ \tan}^{2} y = \frac{ { \sin }^{2} y}{ { \cos }^{2}y }$

So ,

$\frac{ { \sin }^{2}y }{ { \sec }^{2}y - 1 } = \frac{ { \sin}^{2} y}{ { \tan }^{2} y} = \frac{ { \sin }^{2}y }{ \frac{ { \sin}^{2} y}{ { \cos}^{2}y } } = { \cos }^{2} y$

6 0

2 years ago

Compare the following exponential functions: f(x), g(x), and h(x).

Kay [80]

The correct answe would be 4 all functions are at the same rate

6 0

2 years ago

A VERTICAL POLE OF CAST A SHADOW OF 4.5m LONG AT THE SAME TIME A TREE OF HEIGHT 24m LONG CAST A SHADOW OF 6m LONG. FIND THE HEIG

allsm [11]

Answer:

18 metres

Step-by-step explanation:

4.5/6 = x/24

¾= x/24

x = 18 m

6 0

3 years ago