All categories

3 years ago

Isosceles triangle XYZ with angle X congruent angle Z? How do you construct?

Mathematics

1 answer:

KIM [24]3 years ago

8 0

Answer:

The construction is given below.

Step-by-step explanation:

we have to construct an isosceles triangle XYZ with angle X congruent angle Z. The steps of construction are

Step 1 : Construct a segment of any length XZ.

Step 2 : Adjust the compass such that it is greater than half of the segment and then put the needle of compass once at point X and then point Z and draw arc from both points.

Step 3 : Draw the segments from the two endpoints X and Z to the point where the two arcs intersect i.e at point Y.

By above steps of construction Isosceles triangle XYZ with angle X congruent angle Z is constructed.

You might be interested in

What is the percent decrease from 95 to 68 round to the nearest percent

Setler79 [48]

The decrease is (95-68) = 27 .

As a fraction, the decrease is 27/95 of the original amount.

To change any fraction to a decimal, do the division:

(27) divided by (95) = 0.2842...

To change any decimal to a percentage, move the

decimal point two places that ==> way:

0.2842... = 28.42... %Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

I need you to answer with a, b, c, d

solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Then, the zeros of the given quadratic function are:

$\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\ \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Answer: Third option

8 0

1 year ago

Hope someone can help me

Advocard [28]

Hi!

Let's find out how much he has to pay for each of the deals.

Deal 1

£1.75 per mile.

192 x 1.75 = 336

£336

Deal 2

15% off of £680

$\frac{x}{680} \frac{15}{100}$

680 x 15 = 10200

10200/100 = 102

680 - 102 = 578

£578

Deal 3

£90 per day - 1/10

90 x 7 = 630

1/10 of 630 = 63

630 - 63 = 567

£567

The cheapest deal would be Deal 1

Hope this helps! :)

-Peredhel

5 0

3 years ago

The sum of two numbers is 8. Is it possible for the difference of the two numbers to also be 8? Why or why not

r-ruslan [8.4K]

Answer: yes

Step-by-step explanation: because you would get the same number cause anything plus or even divided by 0 then 8 each time you try ex: 8 + 0 = 8

8 - 0 = 8

brainliest plz

4 0

2 years ago

The distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with a mea

zheka24 [161]

Answer:

$301 - $397

Step-by-step explanation:

Using the Empirical rule

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ .

From the above question,

Mean = 349 , standard deviation = 24.

Confidence interval = 95%

Using 2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

μ – 2σ

= 349 - 2(24)

= 349 - 48

= 301

μ + 2σ

349 + 2(24)

= 349 + 48

= 397

Therefore, according to the standard deviation rule, approximately 95% of the students spent between $301 and $397 on textbooks in a semester.

8 0

3 years ago