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babymother [125]
3 years ago
9

Can anyone help me with this question please ??

Mathematics
1 answer:
Anna007 [38]3 years ago
7 0

Answer:

Try 7986

Step-by-step explanation:

(a+b) × height ÷ 2

(a+b are the parallel sides)

102+140=242 ×66= 15972 ÷2= 7986

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Which elements in a set below are integers?12,-3/4,5,-7,2.24,14/7,9
zhuklara [117]

Answer:

12, 5, -7, 14/7, 9

Step-by-step explanation:

Integers are numbers that are either positive or negative and are whole numbers (no decimals).

4 0
3 years ago
Solve the equation. 11 6 = n + 7 9 6 11 ​ =n+ 9 7 ​ start fraction, 11, divided by, 6, end fraction, equals, n, plus, start frac
belka [17]

Answer:

n = 19/18

Step-by-step explanation:

Given:

11/6 = n + 7/9

Find n

11/6 = n + 7/9

Subtract 7/9 from both sides of the equation

11/6 - 7/9 = n + 7/9 - 7/9

11/6 - 7/9 = n

(99-42) / 54 = n

n = 57/54

n = 19/18

4 0
3 years ago
Solve the exponent equation: 4 × 9x -13 × 6x + 9 × 4x = 0
kicyunya [14]
Well x=0

I hope this helps!
4 0
3 years ago
S the expression x3•x3•x3 equivalent to x3•3•3
Artyom0805 [142]
Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes

so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so

x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero

x³=0
x=0

x-∛3=0
x=∛3

x²+x∛3+∛9=0 has no solution

x+∛3=0
x=-∛3

x²-x∛3+∛9=0 has no solution



so the solutions are
x=-∛3, 0, ∛3
3 0
3 years ago
(x+6)(x^2-7x+12)<br> Algebra addition problem to find the area.
lisov135 [29]

Answer:

=x^3-x^2-30x+72

Step-by-step explanation:

Distribute parentheses:

=xx^2+x\left(-7x\right)+x\cdot \:12+6x^2+6\left(-7x\right)+6\cdot \:12

Apply minus - plus rule:

=x^2x-7xx+12x+6x^2-6\cdot \:7x+6\cdot \:12

Simplified:

=x^3-x^2-30x+72

Its complicated but..

7 0
3 years ago
Read 2 more answers
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