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nataly862011 [7]
4 years ago
13

Can anyone please help me with 32,33,36,37,and 40. PLEASE HELP!!

Mathematics
1 answer:
timofeeve [1]4 years ago
4 0
32. y^3-5y^2=0

y^2(y-5)=0

y=0,5

33. 18s^3=50s

18s^2=50

s=+\-sqrt(25/9)=5/3,-5/3

36. 4w^4+40w^2-44=0

4(w^4+10w^2-11)=0

(w^2+11)(w^2-1)=0

w=0,1,+\-sqrt(11)

37. 4z^5=84z^3

4z^2=84

z=+\-sqrt(21)

40. 48p^5=27p^3

48p^2=27

p=+\-sqrt(27/48)=+\-sqrt(9/16)=3/4,-3/4

Any question please feel free to ask. Thanks
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<u>Solution</u><u>:</u>

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From the second fraction, cancel out from both sides (x + 3), the we get:

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<u>Answer</u><u>:</u>

<u>\frac{ {4x}^{2}  - 3x  + 9}{(x + 3)(x + 3)(x - 3)}</u>

Hope you could understand.

If you have any query, feel free to ask.

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