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sergey [27]
3 years ago
13

a school district requires all graduating seniors to take a mathematics test. This year, the rest scores were approximately norm

ally distributed for the 1208 graduating seniors. This mean score on the test was a 74 and the standard deviation was 11. what percent of the graduating seniors had a test above 85? Express your answers to the nearest percent.
Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0
A score of 85 would be 1 standard deviation from the mean, 74.  Using the 68-95-99.7 rule, we know that 68% of normally distributed data falls within 1 standard deviation of the mean.  This means that 100%-68% = 32% of the data is either higher or lower.  32/2 = 16% of the data will be higher than 1 standard deviation from the mean and 16% of the data will be lower than 1 standard deviation from the mean.  This means that 16% of the graduating seniors should have a score above 85%.
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Answer:

b = 40

Step-by-step explanation:

A heater repairman charges $40 to visit a home, plus $70 per hour for the time he spends on the repair.

This situation can be described by an equation of the form y=mx+b , where

x = the time in hours

y = the cost in dollars.

What is the value of b in this equation?

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Writing the above in an equation =

y = $70 × x + $40

y = 70x + 40

Therefore, the value of b in the expression = 40

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B.

Step-by-step explanation:

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3 years ago
choose the equation below that represents the line passing through the point (1, −4) with a slope of 1/2. a.) y − 4 = 1/2(x − 1)
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\displaystyle\frac1a-\frac1h=\frac1h-\frac1b
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b.

\displaystyle h=\frac{2ab}{a+b}
\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}
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\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}
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The other direction can be proved by following the manipulations in the reverse order.
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