Which ordered pairs are solutions to the inequality 2y-x≤-6 ?

Calculate the constant of variation if y varies directly as x.

luda_lava [24]

Answer:

Option A is correct.

The constant of variation is, $-\frac{3}{2}$

Step-by-step explanation:

The Direct variation says that:

if a vary directly to b then, the equation is of the form: a = kb where k is the constant of variation.

Given: if y varies directly as x.

By definition of direct Variation:

y = kx where is the constant of variation.

It is also given that: y = -3 and x =2

Solve for k;

-3 = 2k

Divide both sides by 2 we have;

$k = -\frac{3}{2}$

Therefore, the constant of variation is, $-\frac{3}{2}$

4 0

3 years ago

Need help ASAP!!!!!!

mr Goodwill [35]

Answer:

answer is a

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please help me

Hitman42 [59]

By using algebra properties and trigonometric formulas we find that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equivalent to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ .

<h3>How to prove a trigonometric equivalence by algebraic and trigonometric procedures</h3>

In this question we have trigonometric expression whose equivalence to another expression has to be proved by using algebra properties and trigonometric formulas, including the fundamental trigonometric formula, that is, cos² x + sin² x = 1. Now we present in detail all steps to prove the equivalence:

$\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ Given.

$\frac{1 + \sin x - 1 + \sin x}{1 - \sin^{2}x}$ Subtraction between fractions with different denominator / (- 1) · a = - a.

$\frac{2\cdot \sin x}{\cos^{2}x}$ Definitions of addition and subtraction / Fundamental trigonometric formula (cos² x + sin² x = 1)

$\frac{2\cdot \tan x}{\cos x}$ Definition of tangent / Result

By using algebra properties and trigonometric formulas we conclude that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equal to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ . Hence, the former expression is equivalent to the latter one.

To learn more on trigonometric equations: brainly.com/question/10083069

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4 0

2 years ago

Dakota had $11,211.20 in a savings account with simple interest. She had opened the account with $8,008 exactly 5 years earlier.

Lynna [10]

Answer:

ARE WE ADDING OR MUTILPLYING

Step-by-step explanation:

3 0

3 years ago

Derivative of y= 2^(sin pi x)

laila [671]

Take log of both sides
$\ln y = \ln(2^{\sin \pi x})$
Use log property to get "x" out of the exponent
$\ln y = (\ln 2) (\sin \pi x)$
Differentiate
$\frac{dy}{y} = (\pi \ln 2)(cos \pi x) dx$
Move y to Right side (Note y = original expression)
$\frac{dy}{dx} = (\pi \ln 2) (\cos \pi x) 2^{\sin \pi x}$

In general, whenever you have a function in the form
$y = a^{f(x)}$
The derivative will be
$\frac{dy}{dx} = (\ln a) (f'(x))a^{f(x)}$

3 0

3 years ago