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2 years ago

What is the first digit quotient for 18.6 Please respond ASAP

Mathematics

2 answers:

NISA [10]2 years ago

7 0

I don’t know sorry I’m on the same one and can’t find it out

Free_Kalibri [48]2 years ago

3 0

Answer: 18.6 is your answer because there is nothing behind the 6

Step-by-step explanation: hope this help :)

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The perimeter of a shape shows a car racing track, how far does a car travel in a race which consists of 23 laps 1.2km , 1.2 km

inna [77]

Answer:

110.4km

Step-by-step explanation:

1 lap is equal to 4.8

4.8×23=110. 4

(Need someone to confirm)

6 0

3 years ago

An amount was shared in the ratio 8:6:9:14:12.The largest share was56.What was the total amount shared?

lutik1710 [3]

Answer:

196

Step-by-step explanation:

Since the largest share was 56 and the largest ratio is 14, then

56 ÷ 14 = 4 ← value of 1 part of the share, thus

8 parts = 8 × 4 = 32

6 parts = 6 × 4 = 24

9 parts = 9 × 4 = 36

14 parts = 14 × 4 = 56

12 parts = 12 × 4 = 48

Total the amounts

total = 32 + 24 + 36 + 56 + 48 = 196

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3 years ago

How to solve for X 'Triangles sum Theorem'

guajiro [1.7K]

I guess this will be good example of how to do it

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3 years ago

15 less than 2 times a number is represented by the algebraic expression of 2h - 15. True or false

Advocard [28]

False here are extra words tho make 20 words

8 0

3 years ago

Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec

o-na [289]

Answer:

(a) The probability of the event (X > 84) is 0.007.

(b) The probability of the event (X < 64) is 0.483.

Step-by-step explanation:

The random variable X follows a Poisson distribution with parameter λ = 64.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...$

(a)

Compute the probability of the event (X > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

$=1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007$

Thus, the probability of the event (X > 84) is 0.007.

(b)

Compute the probability of the event (X < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

$=\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483$

Thus, the probability of the event (X < 64) is 0.483.

5 0

3 years ago