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3 years ago

Twenty-five less two times a number, x, is fifteen.

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

8 0

Answer:

x=20

Step-by-step explanation:

2x-25=15

2x=40

x=20

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Step-by-step explanation:

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3 years ago

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You mix 1/2 cup of red paint for every 1/4 cup of blue paint to make 12 cups of

Serhud [2]

4 cups of blue paint and 8 cups of red paint

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3 years ago

The tangent and secant functions are undefined for the same values true or false

Murljashka [212]

Answer:

TRUE

Step-by-step explanation:

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3 years ago

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Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

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Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

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$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

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3 years ago

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andrew-mc [135]

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