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d1i1m1o1n [39]
3 years ago
13

Assume the following information:Spot rate today of Swiss franc = $.60 1-year forward rate as of today for Swiss franc = $.63 Ex

pected spot rate 1 year from now = $.64 Rate on 1 year deposits denominated in Swiss francs = 7% Rate on 1 year deposits denominated in U.S. dollars = 9% From the perspective of U.S. investors with $1,000,000, covered interest arbitrage would yield a rate of return of _______%.
Business
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

12.35%

Explanation:

Data provided in the question:

Spot rate today of Swiss franc = $0.60

1-year forward rate as of today for Swiss franc = $0.63

Expected spot rate 1 year from now = $0.64

Rate on 1 year deposits denominated in Swiss francs = 7%

Rate on 1 year deposits denominated in U.S. dollars = 9%

Amount invested = $1,000,000

Now,

Amount with Swiss franc = Amount invested ÷ Spot rate today of Swiss franc

= $1,000,000 ÷ 0.60

= $1,666,666.67

After 1 year = $1,666,666.67 × ( 1 + 0.07)

= $1,783,333.33

1 year Forward value = $1,783,333.33 × 0.63

= $1123499.99

Therefore,

Yield = [ $1123499.99 - $1,000,000 ] ÷ $1,000,000

= 0.1235

or

= 0.1235 × 100%

= 12.35%

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Perdue Company purchased equipment on April 1 for $38,880. The equipment was expected to have a useful life of three years, or 5
finlep [7]

Answer:

See explanation section.

Explanation:

Requirement 1

We know,

Depreciation expense under the straight-line method = (Cost price - residual value) ÷ useful life

The depreciation expense under the straight-line method remains same in every year.

December 31, Year 1 - depreciation expense = ($38,880 - $1,080) ÷ 3 years.

Depreciation expense = ($37,800 ÷ 3)

Depreciation expense = $12,600

Depreciation expense for year 1 = $12,600 × 9 ÷ 12

Depreciation expense for year 1 = $9,450

Requirement 2

The depreciation expense under the straight-line method remains the same every year.

Year 2 depreciation expense = ($38,880 - $1,080) ÷ 3 years = $12,600

Year 3 depreciation expense = ($38,880 - $1,080) ÷ 3 years = $12,600

Year 4 depreciation expense = ($38,880 - $1,080) ÷ 3 years = $12,600

The equipment will be dissolved after 4 year with a residual value of $1,080.

Requirement 3

The depreciation expense under units-of-activity method = [(Cost price - residual value) ÷ Total operating hours] × usage during the period.

Given,

Cost price = $38,880

residual value = $1,080

Total operating hours =  5,400

Putting the values into the formula, we can get

Depreciation expense rate = ($38,880 - $1,080) ÷  5,400

Depreciation expense rate = $37,800 ÷ 5,400

Depreciation expense rate = $7 per hour.

Depreciation expense for year 1 = $7 per hour × 1,000

Depreciation expense for year 1 = $7,000

Requirement 4

We get from requirement 3

Depreciation expense rate = $7 per hour.

Year 2 Depreciation expense = $7 per hour.

Depreciation expense for year 2 = $7 per hour × 1,900 hour.

Depreciation expense for year 2 = $13,300 hour.

Year 3 Depreciation expense = $7 per hour.

Depreciation expense year 3 = $7 per hour ×  1,600 hour.

Depreciation expense year 3 = $11,200 hour.

Year 4 Depreciation expense = $7 per hour.

Depreciation expense year 4 = $7 per hour ×  900 hour.

Depreciation expense year 4 = $6,300 hour.

Requirement 5

Depreciation rate under the double-declining-balance method = (100% ÷ useful life) ÷ 2

Depreciation rate = (100% ÷ 3 years) × 2

Depreciation rate = 66.67%

Depreciation expense for year 1 = cost price × depreciation rate

Given,

cost price = $38,880

depreciation rate = 66.67%

Putting the values into the formula, we can get

Depreciation expense for year 1 = cost price × depreciation rate

Depreciation expense for year 1 = $38,880 × 66.67%

Depreciation expense for year 1 = $25,921

Requirement 6

In double-declining-balance method, depreciation expense is decreasing.

Book value of year 1 after depreciation = Cost price - year 1 depreciation expense =  $38,880 - $25,921 = $12,959

Depreciation expense for year 2 = Book value of year 1 × depreciation rate.

Depreciation expense for year 2 = ($12,959 × 66.67%) = $8,640

Book value of year 2 after depreciation = Book value of year 1 - Depreciation expense for year 2 = $12,959 - $8,640 = $4,319

Depreciation expense for year 3 = Book value of year 2 × depreciation rate.

Depreciation expense for year 3 = $4,319 × 66.67% = $2,879.50

Book value of year 3 after depreciation = Book value of year 2 - Depreciation expense for year 3 = $4,319 - $2,879.50 = $1,439.5

Depreciation expense for year 4 = Book value of year 3 × depreciation rate.

Depreciation expense for year 4 = $1,439.5 × 66.67% = $960

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A compromise can only be reached when ______.
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What is the present role of the aicpa in the rule-making environment?
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6 0
2 years ago
A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius
anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

T^2 \alpha  a^3

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 \times 10^8 \ km

Therefore, T^2 = ca^3

c= \dfrac{365^2}{(1.496 \times 10^8)^3}

c = 3.9791 \times 10^{20} \ day^2/km^3

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

T^2 = ca^3

a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}

a^3 = 2.9092 \times 10^{27}

a= \sqrt[3]{2.9092 \times 10^{27}}

a = 1.4275 \times 10^9 \ km

However, the velocity for a perihelion = 10.18 km/s

Using the formula

v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})} to calculate the radius, we have:

G = 6.674 \times 10^{-11}

M = 1.989\times 10^{30} \ kg

r = perihelion

v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})

(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30}  ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})

7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}

\dfrac{2}{r} = 1.4824 \times 10^{-12}

r = \dfrac{2}{1.4824 \times 10^{-12}}

r = 1.349 \times 10^{12}

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)

1.349 \times 10^{12}  -  1.425 \times 10^{12}= -  1.425 \times 10^{12} (e)

-7.6\times 10^{10}= -  1.425 \times 10^{12} (e)

\dfrac{-7.6\times 10^{10}}{-  1.425 \times 10^{12}}=  (e)

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

r = 1.425 \times 10^{12} ( 1 + 0.0533)

r = 1.50 \times 10^{12} \ m

to nautical miles, we have:

r = 1.50 \times 10^{12} \times 0.00054  \ nautical \ mile

radius of aphelion \mathbf{r = 8.10 \times 10^8} nautical miles

In respect to the value of a( i.e 1.4275 \times  10^9 \ km)

the body of the solar system is Saturn

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Answer:

The correct answer is option D.

Explanation:

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Out of two moral choices, neither one is unambiguously preferable or acceptable. The situation becomes complex as choosing one alternative will lead to transgression of another.

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