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4 years ago

Show area model of $5.13x24

Mathematics

1 answer:

zaharov [31]4 years ago

7 0

Answer: draw a square on the left side write 5.13 and on the bottom write 24

Step-by-step explanation:

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What is the Slope-Intercept form of the equation of a line that passes through the point (5,-3) and is parallel to the line y =

jolli1 [7]

Answer:

123456098765432112345678900000000000000000000000987654444443221111111111122222233333333333334444444444455555555555556666666666666667777777777888888888889999999000

Step-by-step explanation:

3 0

3 years ago

Solve for the value<br> 14/5 = z/25

Sladkaya [172]

Answer:

z = 70

Step-by-step explanation:

Multiply by 25 on both sides:

14/5 = z/25

25(14/5) = (z/25)

25(14/5) = z

Divide:

25(14/5) = z

25(2.8)‬ = z

Multiply:

25(2.8)‬ = z

70 = z

8 0

3 years ago

Read 2 more answers

At the market, 5 light bulbs cost $9.85 How much do 7 light bulbs cost?

dangina [55]

Its $13.79..... hopefully it helps

7 0

3 years ago

Read 2 more answers

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

5 0

3 years ago

Read 2 more answers

Find the value of f(-3) and g(3) if f(x) = -6x + 3 and g(x) = 3x + 21r.

tekilochka [14]

Answer:

Part 1) $f(-3)=21$

Part 2) $g(3)=9+21r$

Step-by-step explanation:

Part 1) Find the value of f(-3)

we have

$f(x)=-6x+3$

we know that

f(-3) is the value of the function f(x) for x=-3

substitute the value of x=-3 in the function to find f(-3)

$f(-3)=-6(-3)+3$

$f(-3)=18+3$

$f(-3)=21$

Part 2) Find the value of g(3)

we have

$g(x)=3x+21r$

we know that

g(3) is the value of the function g(x) for x=3

substitute the value of x=3 in the function to find g(3)

$g(3)=3(3)+21r$

$g(3)=9+21r$

6 0

3 years ago