Question

100 points I’ll mark you brainliest Answer all please

Answer 1

Step-by-step explanation:

Step 1:  Find $u_1$

$u_1=u_1-u_0$

$u_1 = 3(1)^2-2(1) - (3(0)^2-2(0))$

$u_1 = 3(1) - 2 - (0)$

$u_1=3-2$

$u_1 = 1$

Answer:  $u_1 = 1$

Step 2:  Find $u_6$

$u_6 = u_6-u_5$

$u_6=(3(6)^2-2(6))-(3(5)^2-2(5))$

$u_6=(3(36)-12)-(3(25)-10)$

$u_6 = (108-12) - (75-10)$

$u_6=96 - 65$

$u_6=31$

Answer:  $u_6=31$

Answer 2

Answer:

u1 = 1

u6 = 31

un = 1 + 6(n - 1)

Step-by-step explanation:

Sn = 3n² - 2n

u1 = S1

3(1)² - 2(1)

3 - 2

1

u6 = S6 - S5

[3(6)² - 2(6)] - [3(5)² - 2(5)]

96 - 65

31

un = a + (n - 1)d

u6 = a + 5d

31 = 1 + 5d

5d = 30

d = 6

un = 1 + 6(n - 1)