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Len [333]
3 years ago
7

PLEASE NO FAKES! i really need help i didnt do this math in a minute smh.

Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

15

Step-by-step explanation:

To solve this we need to multiply from left to right:

another way to write 40 is 40/1

so multiply 3/8 and 40/1

(You need to multiply the top with the top and bottom with bottom)

3 times 40 is 120 8 times 1 is 8 so the answer will look like this:

120/8

But we can simplify it:

120 divided by 8 is 15

(If you don't know how to divide long division divide with smaller numbers like 2, 3, 5, 7, and so on)

Alternate way:

Divide by a prime number that can be divided in this case it is 2, stop when that number cannot be divided by that prime number

120: 120/2= 60    60/2= 30     30/2= 15

8: 8/2= 4    4/2= 2     2/2= 1

Hope this helps!

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a random sample of 4 claims are selected from a lot of 12 that has 3 nonconforming units. using the hypergeometric distribution
Sloan [31]

Answer:

The probability that the sample will contain exactly 0 nonconforming units is P=0.25.

The probability that the sample will contain exactly 1 nonconforming units is P=0.51.

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Step-by-step explanation:

We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.

We can write the probability mass function as:

P(x=k)=\frac{\binom{K}{k}\binom{N-K}{n-k}}{\binom{N}{n}}

where k is the number of non-conforming units on the sample of n=4.

We can calculate the probability of getting no non-conforming units (k=0) as:

P(x=0)=\frac{\binom{3}{0}\binom{9}{4}}{\binom{12}{4}}=\frac{1*126}{495}=\frac{126}{495} = 0.25

We can calculate the probability of getting one non-conforming units (k=1) as:

P(x=1)=\frac{\binom{3}{1}\binom{9}{3}}{\binom{12}{4}}=\frac{3*84}{495}=\frac{252}{495} = 0.51

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4 years ago
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Solve this system of linear equations. Separate
Arte-miy333 [17]

Answer:

x = -7, y = -1

Step-by-step explanation:

Solve the following system:

{3 y - 2 x = 11 | (equation 1)

2 y + 3 x = -23 | (equation 2)

Swap equation 1 with equation 2:

{3 x + 2 y = -23 | (equation 1)

-(2 x) + 3 y = 11 | (equation 2)

Add 2/3 × (equation 1) to equation 2:

{3 x + 2 y = -23 | (equation 1)

0 x+(13 y)/3 = -13/3 | (equation 2)

Multiply equation 2 by 3/13:

{3 x + 2 y = -23 | (equation 1)

0 x+y = -1 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x+0 y = -21 | (equation 1)

0 x+y = -1 | (equation 2)

Divide equation 1 by 3:

{x+0 y = -7 | (equation 1)

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Collect results:

Answer: x = -7, y = -1

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3 years ago
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