1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kenny6666 [7]
4 years ago
11

Ed's age is twice that of his brother. When you add Ed's age to his brother's age, you get 36. How old is each brother?

Mathematics
1 answer:
svlad2 [7]4 years ago
6 0

The answer to your question is,

Ed is 27. His brother is 9.

How did I get this answer?

Ed's age is twice that of his brother. So of course, when you divide 36 by 2, you would get 18. They are not twins so this wouldn't be the answer. You need to divide 18 by 2 again. This makes 9. If you add 9 to 27, that makes 36. Which is their ages.

-Mabel <3

You might be interested in
Help meeeeeeeeeeeeeeeeeeeeeee
kykrilka [37]

Answer:

39.8 + ( - 49.5)

Step-by-step explanation:

39.8 + ( - 49.5) \\ 39.8 - 49.5

I hope I helped you^_^

5 0
3 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
aleksley [76]

Answer:

Step 1: The estimate the proportion of tenth graders reading at or below the eighth grade level is 0.2.

Step 2: The 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.181, 0.219).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Suppose a sample of 2845 tenth graders is drawn. Of the students sampled, 2276 read above the eighth grade level.

So 2845 - 2276 = 569 read below, and the estimate of the proportion of tenth graders reading at or below the eighth grade level is:

\pi = \frac{569}{2845} = 0.2, and the answer to step 1 is 0.2.

The sample size is n = 2845

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 - 2.575\sqrt{\frac{0.2*0.8}{2845}} = 0.181

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 + 2.575\sqrt{\frac{0.2*0.8}{2845}} = 0.219

The 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.181, 0.219).

4 0
3 years ago
How many solutions are there to the equation below?
Nata [24]
The answer is c because ther is only one value for x which is -2.5
6 0
3 years ago
Read 2 more answers
What is the least number of party favors Madison should make
Tatiana [17]
The correct answer is b.24
3 0
3 years ago
Read 2 more answers
What is coefficient in front of a variable by itself
jolli1 [7]

Answer:

Step-by-step explanation:

Well Coefficent means its by it self with is called a constant. A coffecient is a number used to mulitpy a varable

6 0
3 years ago
Other questions:
  • 284+ 887 nearest hundred
    6·2 answers
  • Given the triangle below, which of the following is a correct statement?
    10·2 answers
  • The length of a coil of copper wire is a random variable with mean 150 m and standard deviation 4 m. If we choose five coils of
    15·1 answer
  • Apothem = 4 inches what is the perimeter of the triangle
    8·1 answer
  • 5 points
    14·2 answers
  • PLEASE ASAP! GIVING BRAINLIEST!
    6·1 answer
  • Put the quadratic
    12·1 answer
  • __+__+__=30 using 1,3,5,7,9,11, 13, 15 plz help
    5·1 answer
  • What is the length of the midsegment DE? (Round to the nearest tenth, if necessary) SOMEONE PLEASE BRO HELP ME OUT
    9·2 answers
  • If 25 × 26 = n then which divison equation is also true
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!