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slamgirl [31]
3 years ago
15

Which complex number has a distance of |17| from the origin on the complex plane?

Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0

Hello from MrBillDoesMath!

Answer:

z = 17 e^(i t)  

where "t" is a real number

Discussion:

distance (17 e^(it))  =                                        => using deMoivre's formula)

distance ( 17 )  distance ( cost + i sintt) ) =    

17 sqrt(  (cost)^2 + (sint)^2)  =                         =>  (cost)^2 + (sint)^2 =1

17 * 1

= 17

Thank you,

MrB

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4 0
2 years ago
Solve for c.<br> C – 206 = 304<br> Solve c
horrorfan [7]

Answer:

C = 510

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

C - 206 = 304

<u>Step 2: Solve for </u><em><u>C</u></em>

  1. [Addition Property of Equality] Add 206 on both sides:                                C = 510
3 0
3 years ago
Read 2 more answers
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