Here you go let me know if you have questions
Answer:
The probability is 
Step-by-step explanation:
From the question we are told
The population proportion is 
The sample size is 
The number of graduate who had job is k = 209
Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is

Generally the standard deviation of this sampling distribution is

=> 
=> 
Generally the sample proportion is mathematically represented as

=> 
=> 
Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as


From the z table the area under the normal curve to the left corresponding to -3.022 is

=> 
Answer:
y = e^x
Step-by-step explanation:
The fastest way to do this is to use a graphing calc or an online graphing platform and check to see which graph matches the one given.
Well divide them. 2/3=0.666 repeated. So use a bar over the top of the third six.
A. we use the z statistic to solve this problem
z = (x – u) / s
We calculate the value of the sample mean u and standard deviation
s:
u = $30 * 304 = $9120
s = $21 * 304 = $6384
z = (9,600 – 9120) / 6384
z = 0.075
From the normal tables using right tailed test,
P = 0.47
B. At worst 11% means P = 0.11, so the z value at this is
z = -1.23
-1.23 = (x – 9120) / 6384
x = 1267.68